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Talja [164]
3 years ago
14

A trampoline has a jumping surface that is 15.7 ft. long and 12 ft. wide. What is the area of the jumping surface?

Mathematics
2 answers:
Arisa [49]3 years ago
5 0

Answer:

188.4

Step-by-step explanation:

because if you multiply 15.7 and 12 you get 188.4 and that is the area of the jumping space.

allochka39001 [22]3 years ago
4 0

Answer:

area = length×wide=15.7×12=188.4ft²

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Step-by-step explanation:

Check the attachment for the diagram. Sine rule will be used to get the unknown side of the triangle.

According to the rule;

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Given w = 3 in, ∠W=23° and ∠U=73°, on substituting into the equation above to get u we have;

\frac{u}{sin73^{0} } = \frac{3}{sin23^{0} }\\usin23^{0} = 3sin73^{0}\\u = \frac{3sin73^{0} }{sin23^{0} }\\u = \frac{2.87}{0.39} \\u = 7.358\\u = 7.4in

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