The SBA provides information for which group of people?

The average size of a pair of women's shoes sold at a shoe store is size 8, with a standard deviation of 1.5

Troyanec [42]

$Question:—❓$

The average size of a pair of women's shoes sold at a shoe store is size 8, with a standard deviation of 1.5 sizes. If the sizes are normally distributed, what is the percentile rank of at least a size 9. Go to z-table.com

$Answer :— ✔$

HOPE THE PICTURE WILL HELP YOU 
I AM UNABLE TO WRITE HERE 
SO, I HAVE WROTE IN MS WORD 
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6 0

3 years ago

What is a literary requirement for voting ,and how was it used to deny suffrage to certain groups

Misha Larkins [42]

being able to read and write, they would ask blacks a really hard question on theology or something about the constitution and then ask the next guy in line to write the letter

3 0

3 years ago

HEYY I NEED HELP WITH AN AP CALC ASSIGNMENT ASAP

Vladimir79 [104]

CALCULATOR PART

1. The area of R + S is unsigned, meaning you want to find

$\displaystyle\int_a^b\left|f(x)-g(x)\right|\,\mathrm dx$

where $[a,b]$ is the interval between the leftmost and rightmost intersections of $f$ and $g$ .

First use your calculator to find these intersections:

$\cos x=\dfrac{x+1}3\implies x\approx-3.64,x\approx-1.86,x\approx0.889$

so that $a=-3.64$ and $b=0.889$ . Now compute the integral using your calculator:

$\displaystyle\int_a^b\left|f(x)-g(x)|\,\mathrm dx\approx1.662$

2. The volume, using the washer method, is given by the integral

$\displaystyle\pi\int_{-1.86}^{0.889}(|2-g(x)|^2-|2-f(x)|^2)\,\mathrm dx\approx12.078$

3. A circle of radius $r$ has area $\pi r^2$ ; a semicircle with the same radius thus has area $\frac{\pi r^2}2$ . Each cross section of this solid is a semicircle whose diameter is the vertical distance between $f(x)$ and $g(x)$ , or $|f(x)-g(x)|$ . In terms of the diameter $d=2r$ , the area of each semicircle would be $\frac{\pi d^2}8$ . Then the volume of the solid is

$\displaystyle\frac\pi8\int_{-3.64}^{-1.86}|f(x)-g(x)|^2\,\mathrm dx\approx0.0425$

NON-CALCULATOR PART

4. The mean value theorem says that for a function $F$ continuous on an interval $[a,b]$ and differentiable on $(a,b)$ , there is some $c\in(a,b)$ such that

$F'(c)=\dfrac{F(b)-F(a)}{b-a}$

If this $F$ happens to be an antiderivative of $f$ , then we end up with

$f(c)=\displaystyle\frac1{b-a}\int_a^bf(x)\,\mathrm dx$

$\cos x$ is continuous and differentiable everywhere, so the MVT applies. We have $F'(x)=f(x)=\cos x$ , so the MVT tells us there is some $c\in[0,\pi$ such that

$\cos c=\dfrac{\sin\pi-\sin0}{\pi-0}=0$

That is, the average value of $f(x)$ on $[0,\pi]$ is 0. The MVT says there is some $c$ in the interval such that the function takes on the average value itself; this happens for $c=\frac\pi2$ .

5. This question seems to be incomplete...

5 0

4 years ago

Abby’s father owns a small café that focuses on take-outs. However, due to increasing competition the café is running into losse

Thepotemich [5.8K]

To cut costs and minimize losses, Abby can do following things:

Turn of lights when people are not in the restaurant. This will reduce the electricity cost.

Abby can conserve water and dishwasher use. It cuts down on water usage, soap, and energy costs.

Publicize your restaurants in social media with add-ons and offers to attract people. More the people are aware about the restaurant, greater will be the number of people dining in.

Trim down some of the expensive items from the menu.

3 0

3 years ago

Read 2 more answers

URGENT EXTRA POINTS

ss7ja [257]

Answer:

1.6% growth rate

43.75 years = doubling time.

Explanation:

40-24 = 1616/1000 = 0.016 x 100 = 1.6% growth rate

70/1.6 = 43.75 years = doubling time.

8 0

3 years ago