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notsponge [240]
2 years ago
10

Step by step please!

Mathematics
1 answer:
Vitek1552 [10]2 years ago
7 0

Answer:

21

I hope this helped I would appreciate brainliest if possible

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In a company 60% of the workers are men is 880 women work for the company how many workers are there in all
borishaifa [10]
I will do my best to answer this question due to the gramatical errors made making it difficult to read and understand.
assuming that the 880 is the number of women employed that makes up 40% of the company employees
880+ (880*1.5) = 2200 employees total
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3 years ago
What is 275 divided by 38
Triss [41]

Answer:

The answer is 7.2368421053 .

6 0
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kiruha [24]

answer:

4(2+x) and 8 + 4x

since she memorized those scales for EACH of those four lessons, the answer would be that.

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3 years ago
use the information provided to write the standard form equation of each hyperbola vertices:(4,14), (4,-10) foci: (4,15), (4,-11
Evgen [1.6K]
So... if you notice the picture below, based on the given vertices, is a hyperbola with a vertical traverse axis

meaning for the equation, the fraction with the "y" variable is the positive fraction, thus \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1

so... what' the point h,k for the center?  well, just take a peek at the graph, the center is half-way between both vertices, that's h,k

what's the "a" component or the traverse axis... well, is the distance from one vertex to the center, notice the picture, notice how many units from either vertex to the center, that's "a"

now.. what's "b"?  well, "b" comes from the conjugate axis, or the other runnning over the x-axis   hmm the smaller one in this case.... well, we dunno what "b" is

however, we know the distance from either focus, to the center of the hyperbola, and that distance "c", is  \bf c=\sqrt{a^2+b^2}

notice the picture, notice the distance from either focus to the center, that's the distance "c", thus  \bf c=\sqrt{a^2+b^2}\implies c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b

that'd be "b"

bearing in mind that   \bf \cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center= ({{ h}},{{ k}})\\\\ b=\sqrt{c^2-a^2}
\end{cases}

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3 years ago
HELP PLEASE please omg
Nikolay [14]
Drop the questions it’s blank
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3 years ago
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