Answer:
(4 + u)(16 – 4u + u2)
Step-by-step explanation:
64 + u3.
= 43 + u3.
= (4 + u)(42 – 4.u + u2).
= (4 + u)(16 – 4u + u2).
<h3>
Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
F(x)=0
f(x)=y
so where y=0, the x value is the x in f(x)
basically, where the line crosses or touches the x axis, those ar the x values that make the function true
Answer:
yes
Step-by-step explanation:
Answer:
D. I and IV
Step-by-step explanation:
53 is the opposite of -53.
The absolute value of 53 is 53.
<h2><u><em>
Please mark as Brainliest!!!</em></u></h2>
