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larisa86 [58]
3 years ago
15

What is

" alt="\sqrt{44mx^{3} n^{11}" align="absmiddle" class="latex-formula"> simplified
Mathematics
1 answer:
My name is Ann [436]3 years ago
5 0
2xn^5 √ 11mxn
good luck pls mark brainliest
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twice the sum of a number and 6 is equal to 3 times the difference of the number and 8. Find the number
Serhud [2]

In order to solve this problem, we must solve an equation.

First, we need to define our unknown.

Let's call our number "n".


So, the sum of the number and 6 is the same as saying n+6

Then we need to multiply it by 2 (since it's twice the sum)

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This whole thing is equal to three times of the difference of the number and 8

n-8 is equal to the difference between the number and 8, then we need to multiply it by three.

3(n-8)

now, we set both sides equal and solve

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The number is 36

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3 years ago
Solve for x. Round your answer to the nearest hundredth.<br><br> 16^x-7=19
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x=26 is the answer

Step-by-step explanation:

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