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Gre4nikov [31]
3 years ago
11

A display of seed packets contains 24 zucchini seed packets and 28 other seed packets. What is the probability that a randomly s

elected seed packet will contain zucchini seeds? Simplify your answer and write it as a fraction or whole number.
Mathematics
1 answer:
Nonamiya [84]3 years ago
3 0

Answer:

The probability is 6/13

Step-by-step explanation:

Number of zucchini seed packets = 24

Number of other seed packets = 28

Total number of packets = 24 + 28 = 52

Probability is given by

P(E)=\frac{n(E)}{n(s)}\\\\n(E)=24,n(s)=52\\P(E)=\frac{24}{52}\\\\P(E)=\frac{6}{13}

Hence, the required probability is 6/13

You might be interested in
It is estimated that each guest at a party will eat 2/3 pounds of chocolate. How many guest can be served with 6 pounds of choco
alexdok [17]
In this you have to do 6(total) /(Divided) 2/3. And when you do 6/(2/3) you also have to do KCF(keep, change, flip) and that brings you to 18/2 after multiplying across. So the answer would be 9 people.
6 0
3 years ago
300-297+294-291+288-285+...+6-3
vladimir2022 [97]
300 - 297 = 3

294 - 291 = 3

288 - 285 = 3

So, that is a sequence of sums of number 3: 3 + 3 + 3 + .... + 3

How may times will the number 3 be added?

Note that 300 is reduced in 6 units each time => 300 / 6 = 50 => 3 will be added 50 times.

=> 50 * 3 = 150

Answer: 150
7 0
3 years ago
Who’s the the y-value of the vertex of the function f(x)=-(x+8)(x-14)
Ksju [112]

Answer:

The required y-value is -121.

Step-by-step explanation:

There are several ways in which we could approach this problem.  From the two binomial factors (x + 8) and (x - 14), we know that the two roots are x = -8 and x = 14.  The axis of symmetry is the vertical line x = 3.  This value is halfway between x = -8 and x = 14.

Substituting x = 3 into  f(x)= -(x+8)(x-14) results in f(3) = -(11)(-11) = -121.

The vertex is at (3, -121).  The required y-value is -121.

5 0
3 years ago
What is 1/6 divided by 3
Nimfa-mama [501]
1/6÷3
1/6÷3/1
1/6×1/3=
1/18

4 0
2 years ago
Read 2 more answers
Question 4
Irina-Kira [14]

Answer: No, Titus is incorrect.

Step-by-step explanation: Two shapes are <u>congruent</u> when they have the same size and shape, but one is created of rotation, reversion or translation of the other.

So, hexagons FEDCBA and F'E'D'C'B'A' are congruent because they have the same size and shape, however they are reversed and translated from each other, i.e.:

Comparing the coordinates of both hexagons:

F (-6,6) → F' (6, -4)

A (-10,6) → A' (10,-4)

E (-4,4) → E' (4, -6)

B (-12,4) → B' (12, -6)

D (-6,2) → D' (6, -8)

C (-10,2) → C' (10, -8)

We notice that the transformation necessary to transform FEDCBA into F'E'D'C'B'A' is

  • multiply x-coordinate by (-1);
  • subtract y-coordinate by 10;

Therefore, it is (x,y) → ( -x, y-10).

So, Titus is incorrect about the transformations that prove the hexagons are congruent.

6 0
2 years ago
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