Question

A display of seed packets contains 24 zucchini seed packets and 28 other seed packets. What is the probability that a randomly selected seed packet will contain zucchini seeds? Simplify your answer and write it as a fraction or whole number.

Answer 1

Answer:

The probability is 6/13

Step-by-step explanation:

Number of zucchini seed packets = 24

Number of other seed packets = 28

Total number of packets = 24 + 28 = 52

Probability is given by

$P(E)=\frac{n(E)}{n(s)}\\\\n(E)=24,n(s)=52\\P(E)=\frac{24}{52}\\\\P(E)=\frac{6}{13}$

Hence, the required probability is 6/13