All categories

4 years ago

302+ 412 = 577 Use rounding or compatible numbers to estimate the sum

1 answer:

5 0

Rounding numbers or compatible numbers are usually use to be able to calculate a certain number easier and faster.
For the given equation, we have 302 + 412 which is equals to 714 not 577.
Now, let’s look for a rounding or compatible number to estimate the sum.
=> 302, we have 300 as rounding number or compatible numbers
=> 412, we can have 415 as rounding numbers
=> 300 + 415 = 715.
The exact answer is 714 and our estimated is 715.

You might be interested in

If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?

lys-0071 [83]

Answer:

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

$3x^2-(3k-2)x-(k-6) \text{ with }k=2$ :

$3x^2-(3\cdot 2-2)x-(2-6)$

$3x^2-4x+4$

I'm going to solve $3x^2-4x+4=0$ for x using the quadratic formula:

$\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}$

$\frac{4\pm \sqrt{16-16(3)}}{6}$

$\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}$

$\frac{4\pm 4\sqrt{-2}}{6}$

$\frac{2\pm 2\sqrt{-2}}{3}$

$\frac{2\pm 2i\sqrt{2}}{3}$

Let's see if uv=u+v holds.

$uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}$

Keep in mind you are multiplying conjugates:

$uv=\frac{1}{9}(4-4i^2(2))$

$uv=\frac{1}{9}(4+4(2))$

$uv=\frac{12}{9}=\frac{4}{3}$

Let's see what u+v is now:

$u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}$

$u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}$

We have confirmed uv=u+v for k=2.

4 0

3 years ago

REPOST*

xeze [42]

-6-3-5

Hence inequality will be

$\\ \sf\longmapsto -6\leqslant 5$

#2.

But we need inequality

$\\ \sf\longmapsto 3\leqslant 5$

The inequality given by

$\\ \sf\longmapsto -6\leqslant 3\leqslant 5$

7 0

3 years ago

Read 2 more answers

Use prime factorization to find the least common multiple of 54 and 36

irinina [24]

Answer: 108

Explanation:

GCF(36,54) = 18
LCM(36,54) = ( 36 × 54) / 18
LCM(36,54) = 1944 / 18
LCM(36,54) = 108

6 0

3 years ago

Consider continuous functions f, g, h, and k. Then complete the statements.

solmaris [256]

Answer:

g and g

Step-by-step explanation:

just did

4 0

3 years ago

Read 2 more answers

The perimeter of this Hexagon is 162 cm. Each longer side measures 1 cm more than twice a shorter side. Find the length of the l

Elis [28]

Let x represent the shorter sides, then 2x + 1 would represent the longer sides. There are four short sides and two long sides. The perimeter is 162 cm. The equation: 4x + 2(2x + 1) = 162 4x + 8x + 2 = 162 8x + 2 = 162 Subtract 2 from both sides. 8x = 160 Divide both sides by 8. x = 20 The shorter sides are 20 cm in length. The longer sides are 2x + 1, or 41 cm in length. Check: 4 * 20 + 2 * 41 = 162 80 + 82 = 162 162 = 162, values check.

5 0

4 years ago