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3 years ago

302+ 412 = 577 Use rounding or compatible numbers to estimate the sum

1 answer:

5 0

Rounding numbers or compatible numbers are usually use to be able to calculate a certain number easier and faster.
For the given equation, we have 302 + 412 which is equals to 714 not 577.
Now, let’s look for a rounding or compatible number to estimate the sum.
=> 302, we have 300 as rounding number or compatible numbers
=> 412, we can have 415 as rounding numbers
=> 300 + 415 = 715.
The exact answer is 714 and our estimated is 715.

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James had $15,345.21 withheld from his income one year. He

puteri [66]

Answer:

$2,373.23

Step-by-step explanation:

-Tax refund is determined by comparing your total income tax to the amount that was withheld for federal income tax.

-Assuming that the amount withheld for federal income tax was greater than your income tax for the year, you will receive a refund for the difference.

#Refund =Withheld -Actual Tax liability=$15345.21-$12971.98=$2,373.23

Hence James' tax refund will be $2,373.23

5 0

3 years ago

A state end-of-grade exam in American History is a multiple-choice test that has 50 questions with 4 answer choices for each que

Assoli18 [71]

Answer:

Q1) The student has a 0.01% probability of passing the test.

Q2) She has a 99.91% probability of passing in the test.

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he gets it correct, or he gets it wrong. So we solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

For this problem, we have that:

Question 1.

There are 50 questions, so $n = 50$ .

The student is going to guess each question, so he has a $\pi = \frac{1}{4} = 0.25$ probability of getting it right.

He needs to get at least 25 question right.

So we need to find $P(X \geq 25)$ .

Using a binomial probability calculator, with $n = 50$ and $\pi = 0.25$ we get that $P(X \geq 25) = 0.0001$ .

This means that the student has a 0.01% probability of passing the test.

Question 2.

Now, we need to find $P(X \geq 25)$ with $\pi = 0.70$ . So $P(X \geq 25) = 0.9991$

She has a 99.91% probability of passing in the test.

7 0

3 years ago

Read 2 more answers

A rectangle has sides that measure x + 1/4

maksim [4K]

Answer:

6x + 5/6

Step-by-step explanation:

2(x + 1/4) + 2(2x + 1/3)

2x + 1/2 + 4x + 2/3

6x + 5/6

6 0

3 years ago

Determine the dependent variable in the statement:

Mice21 [21]

Answer:

Step-by-step explanation:

The speed depends on how hard Sam throws the ball so the dependant variable would be the speed.

4 0

3 years ago

2x² - 5x+1 has roots alpha and beta. Find alpha⁴+beta⁴ without solving the equation.

shepuryov [24]

Answer:

Step-by-step explanation:

$\alpha+\beta=\dfrac{5}{2} \\\\\alpha*\beta=\dfrac{1}{2} \\\\\alpha^2+\beta^2=\dfrac{21}{4} \ (see\ previous\ post)\\\\(\alpha+\beta)^4=\dfrac{625}{16} \\\\=\alpha^4+\beta^4+4*\alpha^3*\beta+6*\alpha^2*\beta^2+4*\alpha*\beta^3\\\\=\alpha^4+\beta^4+4*(\alpha*\beta)(\alpha^2+\beta^2)+6*\alpha^2*\beta^2\\\\\alpha^4+\beta^4=(\alpha+\beta)^4-4*(\alpha*\beta)(\alpha^2+\beta^2)-6*\alpha^2*\beta^2\\\\= \dfrac{625}{16} -4*\dfrac{1}{2} *\dfrac{21}{4} -6*(\dfrac{1}{2})^2 \\\\$

$= \dfrac{625}{16}- \dfrac{168}{16}-\dfrac{24}{16}\\\\\\= \dfrac{433}{16}$

7 0

3 years ago