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7nadin3 [17]
3 years ago
15

Check the ONE factor that is NOT used to determine the best channel to send a message. *

Business
1 answer:
mihalych1998 [28]3 years ago
3 0

Answer:

Concern of your audiences response.

Explanation:

Communication can be defined as a process which typically involves the transfer of information from one person (sender) to another (recipient), through the use of semiotics, symbols and signs that are mutually understood by both parties.

The Sender Message Channel Receiver (SMCR) model of communication was developed and created by David Berlo in 1960. SCMR was developed from the Shannon-Weaver model of communication of 1949.

The SCMR model of communication comprises of four (4) main components and these are;

1. Sender (S) : this is typically the source of information (message) or the originator of a message that is being sent to a receiver. Thus, they are simply the producer of a message.

2. Channel (C) : this is the medium used by the sender for the dissemination or transmission of the message to the recipient. For example, telephone, television, radio, newspapers, billboards etc.

3. Message (M) : this is the information or data that is being sent to a recipient by a sender. It could be in the form of a video, audio, text message etc.

4. Receiver (R) : this is typically the destination of information (message) or the recipient of a message that is being sent from a sender. Thus, the receiver is any individual who is able to read, hear or see and process the message being sent or communicated in the communication process.

The factors used to determine the best channel to send a message includes the following;

I. The importance of a message

II. The amount and speed of feedback from the receiver (recipient).

III. The need for a permanent record of the message.

IV. Cost of the channel.

V. The degree of formality desired by the sender of the message.

VI. Confidentiality and sensitivity of the message being sent.

VII. The preference and level of technical expertise of the receiver (recipient).

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The Engine Division provides diesel engines for the Motor Home Division of a company. The standard unit costs for Engine Divisio
Lisa [10]

Answer:

The best transfer price to avoid transfer price problems is $2,310

Explanation:

Transfer Price = Variable cost + Fixed Fee

Variable Cost = Direct Material + Direct labor + Variable Overhead

                       = 600 + 1,200 + 300

                       = 2,100

Transfer Price = Variable cost + Fixed Fee

                        = 2,100 + 210

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Therefore, The best transfer price to avoid transfer price problems is $2,310

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3 years ago
Mike, a minor, buys some real estate as an investment. The contract obligates Mike to make monthly installment payments for 10 y
yawa3891 [41]

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Explanation:

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3 years ago
9.To what part of an industry does a worker's education contribute?
laiz [17]

Answer:

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Explanation:

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4 0
3 years ago
Repair calls are handled by one repairman at a photocopy shop. Repair time, including travel time, is exponentially distributed,
wolverine [178]

Answer:

the average number of customers awaiting repairs = 0.30

the system utilization = 42

the amount of time that the repairman is not out on a call is  = 4.64 hours

the probability of two or more customers in the system = 0.1764

Explanation:

Given that :

Repair time, including travel time =  mean of 1.6 hours per call.

Requests for copier repairs = mean rate of 2.1 per eight-hour day

i.e mean rate R = 2.1/day

Time = 8 hours

thus; mean rate μ = 8 hours/ 1.6 hours = 5

(a)

Let the average number of customers awaiting repairs be I_i :

I_i = \dfrac{R^2}{\mu (\mu-R)}

I_i = \dfrac{2.1^2}{5 (5-2.1)}

I_i = \dfrac{4.41}{5 (2.9)}

I_i = \dfrac{4.41}{14.5}

\mathbf{I_i = 0.30}

the average number of customers awaiting repairs = 0.30

(b) Determine system utilization.

The system utilization is determined as follows:

\delta = \dfrac{R}{\mu}

\delta = \dfrac{2.1}{5}

{\delta = 0.42}

\mathbf{\delta = 42}

(c) The amount of time during an eight-hour day that the repairman is not out on a call is calculated as :

Percentage of Idle time = 1 - \delta

Percentage of Idle time = 1 - 0.42

Percentage of Idle time = 0.58

However during an 8 hour day; The amount of time that the repairman is not out on a call is = 0.58 × 8 = 4.64 hours

(d)

the probability of two or more customers in the system by assuming Poisson Distribution is:

P(N ≥ 2) = 1 - (P₀+ P₁)

where;

P₀ = 0.58

P₁ = 0.58  × 0.42 = 0.2436

P(N ≥ 2) = 1 - ( 0.58 + 0.2436)

P(N ≥ 2) = 1 - 0.8236

P(N ≥ 2) = 0.1764

Thus; the probability of two or more customers in the system is 0.1764

7 0
3 years ago
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