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3 years ago

Heat Shield Rock 5. How did Heat Shield Rock get its name?

Chemistry

1 answer:

jok3333 [9.3K]3 years ago

8 0

Answer:

Heat Shield Rock is a basketball-sized iron-nickel meteorite found on the Meridiani Planum plain of Mars by the Mars rover Opportunity in January 2005.

Heat Shield Rock

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Prediction for Scandium (II) and Cl

SCORPION-xisa [38]

Answer:

(a) Eka-aluminum and gallium are two names of the same element as Eka-Aluminium has almost exactly the same properties as the actual properties of the gallium element. The properties: atomic mass, density, melting point, formula of chloride and formula of oxide are almost the same.

Explanation:

Scandium - Eka boron.

(ii) Gallium - Eka aluminium.

(iii) Germanium - Eka silicon.

3 0

3 years ago

Consider the following reaction between mercury(II) chloride and oxalate ion:

siniylev [52]

Answer : The reaction rate will be, $1.9\times 10^{-4}M/s$

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

$2HgCl_2(aq)+C_2O_2^{4-}(aq)\rightarrow 2Cl^-(aq)+2CO_2(g)+HgCl_2(s)$

Rate law expression for the reaction:

$\text{Rate}=k[HgCl_2]^a[C_2O_2^{4-}]^b$

where,

a = order with respect to $HgCl_2$

b = order with respect to $C_2O_2^{4-}$

Expression for rate law for first observation:

$3.2\times 10^{-5}=k(0.164)^a(0.15)^b$ ....(1)

Expression for rate law for second observation:

$2.9\times 10^{-4}=k(0.164)^a(0.45)^b$ ....(2)

Expression for rate law for third observation:

$1.4\times 10^{-4}=k(0.082)^a(0.45)^b$ ....(3)

Expression for rate law for fourth observation:

$4.8\times 10^{-5}=k(0.246)^a(0.15)^b$ ....(4)

Dividing 1 from 2, we get:

$\frac{2.9\times 10^{-4}}{3.2\times 10^{-5}}=\frac{k(0.164)^a(0.45)^b}{k(0.164)^a(0.15)^b}\\\\9=3^b\\(3)^2=3^b\\b=2$

Dividing 3 from 2, we get:

$\frac{2.9\times 10^{-4}}{1.4\times 10^{-4}}=\frac{k(0.164)^a(0.45)^b}{k(0.082)^a(0.45)^b}\\\\2=2^a\\a=1$

Thus, the rate law becomes:

$\text{Rate}=k[HgCl_2]^1[C_2O_2^{4-}]^2$

Now, calculating the value of 'k' by using any expression.

Putting values in above rate law, we get:

$3.2\times 10^{-5}=k(0.164)^1(0.15)^2$

$k=8.7\times 10^{-3}M^{-2}s^{-1}$

Now we have to determine the reaction rate when the concentration of $HgCl_2$ is 0.135 M and that of $C_2O_2^{-4}$ is 0.40 M.

$\text{Rate}=k[HgCl_2]^1[C_2O_2^{4-}]^2$

$\text{Rate}=(8.7\times 10^{-3})\times (0.135)^1\times (0.40)^2$

$\text{Rate}=1.9\times 10^{-4}M/s$

Therefore, the reaction rate will be, $1.9\times 10^{-4}M/s$

6 0

4 years ago

Explain what the name scandium(III) oxide means

Archy [21]

<span>The roman numeral 3 represents the oxidation of the metal, scandium. </span>

3 0

3 years ago

How many outer electrons does cesium and magnesium have?

Tanzania [10]

The outer electrons of an element are called the valence electrons. They help make an element stable.

Cesium : 1 valence electron<span>.

Magnesium : 2 valence electrons</span>

6 0

3 years ago

Which property among the following is best suitable for metalloids

QveST [7]

Answer:

2. Have the property of metals and non-metals

Explanation:

A metalloid is a substance that posseses the characteristics of both metals and non-metals. In other words, it can be said to be an intermediary between metals and nonmetals.

According to this question, a metalloid

4 0

3 years ago

Heat Shield Rock 5. How did Heat Shield Rock get its name?​

Heat Shield Rock 5. How did Heat Shield Rock get its name?