Lewis dot structure for F2(g)

Instead of developing embryo inside the egg, the embryo grows and develops inside the mother's womb until the baby is born. This

ra1l [238]

Answer:

mammal

Explanation:

mammals are the types of animals who dont have eggs

8 0

2 years ago

The speed of sound through air at 20°C is 343 meters per second. The speed of sound through fresh water at 20°C is 1,482 meters

AVprozaik [17]

Answer:

C. 5960 meters per second

3 0

2 years ago

When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. 2 Al ( s ) + 6 HCl ( aq ) ⟶ 2 AlCl 3 ( aq )

Dovator [93]

Answer:

The volume of hydrogen gas produced at STP is 4.90 liters.

Explanation:

$2Al (s) + 6 HCl (aq)\rightarrow 2 AlCl_3 (aq) + 3 H_2 (g)$

Moles of aluminium = $\frac{3.60 g}{27 g/mol}=0.1333 mol$

According to reaction , 2 moles of aluminium gives 3 moles of hydrogen gas.

Then 0.1333 moles of aluminium will give:

$\frac{3}{2}\times 0.1333 mol=0.2 moles$ of hydrogen gas

Volume of 0.2 moles of hydrogen gas at STP = V

Temperature at STP = T = 298.15 K

Pressure at STP = P = 1 atm

n = 0.2 mol

PV = nRT (Ideal gas equation)

$V=\frac{nRT}{P}=\frac{0.2mol\times 0.0821 atm L/mol K\times 298.15 K}{1 atm}=4.8956 L\approx 4.90 L$

The volume of hydrogen gas produced at STP is 4.90 liters.

4 0

3 years ago

A certain reaction has an activation energy of 66.41 kJ/mol. At what Kelvin temperature will the reaction proceed 3.00 times fas

swat32

Answer : The temperature will be, 392.462 K

Explanation :

According to the Arrhenius equation,

$K=A\times e^{\frac{-Ea}{RT}}$

or,

$\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_1$ = rate constant at $T_1$ = $K_1$

$K_2$ = rate constant at $T_2$ = $3K_1$

$Ea$ = activation energy for the reaction = 66.41 kJ/mole = 66410 J/mole

R = gas constant = 8.314 J/mole.K

$T_1$ = initial temperature = 293 K

$T_2$ = final temperature = ?

Now put all the given values in this formula, we get:

$\log (\frac{3K_1}{K_1})=\frac{66410J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{293K}-\frac{1}{T_2}]$

$T_2=392.462K$

Therefore, the temperature will be, 392.462 K

8 0

3 years ago

What is the empirical formula of a compound containing 24.56% potassium, 34.81% manganese, and 40.50% oxygen?

grin007 [14]

It would be the last anwer

6 0

3 years ago

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