Answer:
v=0.94 m/s
Explanation:
Given that
M= 5.67 kg
k= 150 N/m
m=1 kg
μ = 0.45
The maximum acceleration of upper block can be μ g.
a= μ g ( g = 10 m/s²)
The maximum acceleration of system will ω²X.
ω = natural frequency
X=maximum displacement
For top stop slipping
μ g =ω²X
We know for spring mass system natural frequency given as

By putting the values

ω = 4.47 rad/s
μ g =ω²X
By putting the values
0.45 x 10 = 4.47² X
X = 0.2 m
From energy conservation


150 x 0.2²=6.67 v²
v=0.94 m/s
This is the maximum speed of system.
Answer:

Explanation:
From the question we are told that:
Diameter 
Radius 
Potential 
Generally the equation for Potential on spere is mathematically given by

Therefore

Where

Therefore


By Kirchoff's law in left side loop

similarly kirchoff's law in right side loop

also by junction law we know that

now by plug in all values we have




So by solving above equations we have



The requirement is to change the °F to °C scale. That is;
T(°C) = [T(°F) - 32]/1.8
Substituting;
T(°C) = [428 - 32]/1.8 = 396/1.8 = 220 °C.
Therefore, 428°F will be 220°C on Celsius scale.