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Ludmilka [50]
3 years ago
9

The moons phases are caused by

Physics
1 answer:
Darina [25.2K]3 years ago
7 0
C. The alignment of the Earth, moon, and sun.
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An airplane travels 1200 km in 90 minutes. What is the average speed in m/s for this trip?
gladu [14]

Answer:

the answer is 1333.33m/s

3 0
3 years ago
A 5.67-kg block of wood is attached to a spring with a spring constant of 150 N/m. The block is free to slide on a horizontal fr
nikklg [1K]

Answer:

v=0.94 m/s

Explanation:

Given that

M= 5.67 kg

k= 150 N/m

m=1 kg

μ = 0.45

The maximum acceleration of upper block can be μ g.

 a= μ g                          ( g = 10 m/s²)

The maximum acceleration of system will ω²X.

ω = natural frequency

X=maximum displacement

For top stop slipping

μ g  =ω²X

We know for spring mass system natural frequency given as

\omega=\sqrt{\dfrac{k}{M+m}}

By putting the values

\omega=\sqrt{\dfrac{150}{5.67+1}}

ω = 4.47 rad/s

μ g  =ω²X

By putting the values

0.45 x 10 = 4.47² X

X = 0.2 m

From energy conservation

\dfrac{1}{2}kX^2=\dfrac{1}{2}(m+M)v^2

kX^2=(m+M)v^2

150 x 0.2²=6.67 v²

v=0.94 m/s

This is the maximum speed of system.

7 0
3 years ago
Read 2 more answers
An electrostatic paint sprayer has a 0.17 m-diameter metal sphere at a potential of 25.0 kV that repels charged paint droplets o
Troyanec [42]

Answer:

q=0.236uC

Explanation:

From the question we are told that:

Diameter d=0.17m

Radius r=0.17/2=>0.085

Potential E=25.0kV

Generally the equation for Potential on spere is mathematically given by

E=\frac{1}{4 \pi e_0}*\frac{q}{r}

Therefore

q=\frac{25*10^3*0.085}{\frac{1}{4 \pi e_0}}

Where

\frac{1}{4 \pi e_0}=9*10^9

Therefore

q=\frac{25*10^3*0.085}{(9*10^9}}

q=0.236uC

4 0
3 years ago
Find the currents flowing in the circuit in the figure below. (Assume the resistances are
Nitella [24]

By Kirchoff's law in left side loop

E_1 + E_2 = {r_1 + R_1 + R_4)I_1 + (R_2 + r_2) I_3

similarly kirchoff's law in right side loop

E_3 - E_4 - E_2 = (r_3 + r_4 + R_3)I_2 - (R_2 + r_2)I_3

also by junction law we know that

I_1 = I_2 + I_3

now by plug in all values we have

18 + 3 = (0.5 + 8 + 15)I_1 + (10 + 0.25)I_3

21 = 23.5I_1 + 10.25I_3

12 - 24 - 3 = (0.75 + 0.25 + 12)I_2 - (10+ 0.25)I_3

-15 = 13I_2 - 10.25I_3

So by solving above equations we have

I_1 = 0.492 A

I_2 = -0.428 A

I_3 = 0.920 A

6 0
4 years ago
Octane is an important component of gasoline. Octane will ignite at a temperature of 428°F. What is this temperature on the Cels
xxMikexx [17]
The requirement is to change the °F to °C scale. That is;

T(°C) = [T(°F) - 32]/1.8

Substituting;

T(°C) = [428 - 32]/1.8 = 396/1.8 = 220 °C.

Therefore, 428°F will be 220°C on Celsius scale.
5 0
4 years ago
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