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balu736 [363]
3 years ago
8

Orion is visible on winter evenings in the northern hemisphere but not summer evenings because of_______________.

Physics
1 answer:
Bess [88]3 years ago
3 0

Answer:

c. the location of Earth in its orbit.

Explanation:

It is known that the earth orbits the sun once every 365 days, during this time the<u> constellations that are visible in the sky are changing</u>.

This is due to the fact that depending on the position, we have access to different parts of the celestial tomb, that is, the stars and constellations visible from earth.

This is why Orion is visible in winter but not in summer, since in summer it is in a <u>different part of the orbit</u> and with visibility towards different constellations.

the answer is c. the location of Earth in its orbit.

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an athlete whirls a 7.00 kg hammer tied to the end of a 1.3 m chain in a horizontal circle the hammer moves at the rate of 1.0 r
ElenaW [278]

Answer:

The answer to your question is a = 1.3 m/s²

Explanation:

Centripetal acceleration is the motion of a body that transverse a circular path.

Data

mass = 7 kg

radius = r = 1.3 m

angular rate = w = 1.0 rev/s

centripetal acceleration = a = ?

Formula

a = rw²

Substitution

a = (1.3)(1)²

Simplification and result

a = 1.3 m/s²

4 0
3 years ago
How Can We Ensure That We Continue To Have Adequate Supplies Of Fresh Water To Meet Our Needs?
Alex17521 [72]

-- Conserve.  Don't use more than we need.  There isn't any more of it.

-- Conserve.  Don't pollute what we have.  There isn't any more of it.

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4 0
3 years ago
4. Magnets with one pole are now routinely made.<br> True or False
weqwewe [10]

Answer:

False

Explanation:

5 0
3 years ago
Which state of matter contains particles that move slightly in a fixed posistion
Pavlova-9 [17]
Solid moves slightly in a fixed position

6 0
4 years ago
Read 2 more answers
A brass statue with a mass of 0.40 kg and a density of 8.00×103kg/m3 is suspended from a string. When the statue is completely s
Mars2501 [29]

Answer:

ρ = 1469  kg/m³

Explanation:

given,

mass of statue = 0.4 Kg

density of statue = 8 x 10³ kg/m³

tension in the string = 3.2 N

density of the fluid = ?

Volume of the statue

V = \dfrac{0.4}{8\times 10^3}

V = 5 x 10⁻⁵ m³

W = ρ g V

W = ρ x 9.8 x 5 x 10⁻⁵

now, tension on the string will be equal to

T = mg - W

3.2 = 0.4 x 9.8 - ρ x 9.8 x 5 x 10⁻⁵

ρ x 9.8 x 5 x 10⁻⁵ = 0.72

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8 0
3 years ago
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