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ss7ja [257]
4 years ago
14

Static discharges occur when _____.

Physics
2 answers:
kvasek [131]4 years ago
5 0
B. the air suddenly becomes charged between two oppositely charged objects
Naddika [18.5K]4 years ago
3 0

Answer:

B. the air suddenly becomes charged between two oppositely charged objects

Explanation:

When two equal and opposite charge density objects are placed near each other then due to huge charge density it will create large electric field in the air gap between two charge objects.

Due to this large electric field the electric dipoles of gases present in the air gap will experience large force in opposite direction due to which the dipole has tendency to breakdown.

Due to this breakdown of dipoles a discharge on two objects will occurs which is known as static discharge of air or breakdown of air.

So here correct answer will be

B. the air suddenly becomes charged between two oppositely charged objects

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The magnitude of a vector can be different in different coordinate systems. The magnitude of a vector can be different in differ
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False.

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3 years ago
A compound wall consists of parallel layers of two different materials, 10 cm of brick and 2 cm of wood. If the difference of te
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The temperature difference between the wooden wall is 16⁰C, and the heat current per square metre of the wall is 7,325 W/m².

<h3>Temperature difference between the wooden wall</h3>

The temperature difference between the wooden wall is calculated as follows;

  • Let the brick wall =  wall A
  • Let the wooden wall = wall B
  • Let the area of the walls = A

\frac{dQ_A}{dt } = \frac{dQ_B}{dt} \\\\\frac{K_A \Delta T_A \times  A}{L_A} = \frac{K_B \Delta T _B \times A}{L_B}\\\\\frac{K_A \Delta T_A }{L_A} = \frac{K_B \Delta T _B}{L_B}\\\\\frac{0.5 \times 20}{0.1} = \frac{0.125 \times \Delta T _B }{0.02} \\\\100 = 6.25\Delta T _B\\\\\Delta T _B = \frac{100}{6.25} \\\\\Delta T _B = 16 \ ^oC

<h3 /><h3>Heat flowing in the walls</h3>

Q = KL(ΔT)

Q = 0.5 x 0.1 x (20 + 273)

Q = 14.65 W

<h3>Heat current per square meter of the Walls</h3>

QA = W/A

QA = (14.65)/A

  • Let the area of the wall = 10 cm x 2 cm = 0.1 m x 0.02 m = 0.002 m².

QA = 14.65/0.002

QA = 7,325 W/m²

Learn more about thermal conductivity here: brainly.com/question/11213835

4 0
3 years ago
What is the G.P.E of 675 newtons on 26000 meter mountain
vagabundo [1.1K]
GPE=mgh, where m=mass, g=acceleration due to gravity, h=height
We have a force of 675N already, so mg=675N

<span>GPE=mgh=675(26000)=17.55x10^6J</span>
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3 years ago
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