For the answer to the question above, we are given with two isotopes of oxygen, one that is stable O-18 and O-19 that is unstable. The stability of a nucleus is relative to the nuclear binding energy and mass defect. In this case, nuclear binding energy is always. So the answer is <span>O-19 has a mass defect; O-18 does not have a mass defect.</span>
Answer:
A) 17.7 m/s
B) 15.98 m
C) Zero
E) 9.8 m/s²
Explanation:
given information
distance, h = - 34 m
time, t = 5 s
A) What is the initial speed of the egg?
h - h₀ = v₀t - t², h₀ = 0
- 34 = v₀ 5 - \frac{1}{2} 9.8 5²
- 34 = 5 v₀ - 122.5
v₀ = 122.5 - 34/5
= 17.7 m/s
B) How high does it rise above its starting point?
v² = v₀² - 2gh
v = 0 (highest point)
2gh = v₀²
h = v₀²/2g
= 17.7²/2 (9.8)
= 15.98 m
C) What is the magnitude of its velocity at the highest point?
v = 0 (at highest point)
E) What are the magnitude and direction of its acceleration at the highest point?
g= 9.8 m/s², since the egg is moved vertically, the acceleration is the same as the gravitational acceleration.
By angular speed, the frequency is 2.39 Hz.
We need to know about the angular speed of harmonic oscillation. the angular speed can be determined as
ω² = k / m
where ω is angular speed, k is spring constant, and m is the mass.
The angular speed can be calculated by
ω = 2πf
Hence,
ω² = k / m
(2πf)² = k / m
k = (2πf)² / m
where f is frequency.
From the question above, we know that:
m1 = 0.6 kg
f1 = 3 Hz
m2 = 0.38 kg
The spring is same, hence the spring constant is the same
k1 = k2
(2πf1)² / m1 = (2πf2)² / m2
f1² / m1 = f2² / m2
3² / 0.6 = f2² / 0.38
f2² = 5.7
f2 = 2.39 Hz
Find more on angular speed at: brainly.com/question/6860269
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