$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\U (-1,4)\quad\implies\quad x_1=-1\,,\ \ y_1=4 \\\\B (8,5)\quad\implies\quad x_2=8\,,\ \ y_2=5\\\\\frac12d=\frac23\sqrt{(8+1)^2+(5-4)^2}=\frac23\sqrt{81+1}=\frac23\sqrt{82}\approx6.037$

7 0

3 years ago

Amy, a nature photographer, randomly sampled photographs she took within the last year. She wanted to find out how many of her p

Sveta_85 [38]

The Constructed confidence interval for the proportion of her photographs taken within the last year contained flowers is

$CI\ E(0.57,0.65)$

From the question we are told that:

The proportion of photographs that had flowers P= 0.61

Margin of error of M.E= 0.04

Generally, the equation for Confidence interval for proportion is mathematically given by

$CI=0.61 \pm 0.04$ P \pm M.E

Therefore Confidence interval is

$CI=0.61 \pm 0.04$

And can also be written as

$CI\ E((0.61+0.04),0.61-0.04))$

$CI\ E(0.57,0.65)$

In conclusion the Confidence interval is

$CI\ E(0.57,0.65)$

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4 0

3 years ago