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mrs_skeptik [129]
3 years ago
9

What is the value of the coefficient of the fourth term of the expansion of (a+b)^5 ?

Mathematics
1 answer:
melomori [17]3 years ago
6 0

Answer:

I don't know if you wanted it expanded using "Pascal's Triangle" or "Binomial Theorem" but either way is the same. Your expanded equation is:

a^5 + 5a^4b + 10a^3b^2 + 10a^2b^3 + 5ab^4 + b^5

I hope this is any help to you, have a nice day.

Step-by-step explanation:

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Hello please please help me with this question now please please
Cerrena [4.2K]

Answer:

Step-by-step explanation:

As x increases four units from -4 to 0, y decreases four units from 0 to -4

slope m = Δy/Δx = -4/4 = -1

The y intercept is at (0, -4) so b = -4

y = -1x + -4

y = - x - 4

as m is negative, slope is negative

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Explain how this method is correct...2 times 3 is 6, and 6 times 5 is 30.
ikadub [295]

Answer:

2+2+2=6 and 6+6+6+6+6=30

Step-by-step explanation:

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2 years ago
Consider the surface f (x comma y comma z )f(x,y,z)equals=negative 2 x squared plus 2 y squared minus 3 z squared plus 3 equals
trapecia [35]

Answer:

a) (8,8,-6)

b) 4x+4y+3z = -3

Step-by-step explanation:

a)

The surface is given by the equation  

f(x,y,z) = 0 where

f(x,y,z)=-2x^2+2y^2-3z^2+3

The gradient of this function is the vector

(\frac{\partial f}{\partial x},\frac{\partial f}{\partial y},\frac{\partial f}{\partial z})=(-4x,4y,-6z)

If we evaluate it in the point P = (-2,2,1) we obtain the point

(8,8,-6)

b)

The vectors with their tails at P are of the form  

(-2,2,1)-(x,y,z) = (-2-x, 2-y, 1-z)

as they must be orthogonal to the gradient, they must be orthogonal to the vector (8,8,6) so their inner product is 0

(-2-x,2-y,1-z)\cdot(8,8,6)=0\Rightarrow -16-8x+16-8y+6-6z=0\Rightarrow 4x+4y+3z=-3

and the equation of the desired plane is

4x+4y+3z = -3

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3 years ago
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