Ask question

Ask question

All categories

3 years ago

8

A lamp shade has a radius of 9 inches. What is the circumference of the top of the shade? Use 3.14 to approximate pi. Round your

answer to the nearest whole number.

2 answers:

Black_prince [1.1K]3 years ago

4 0

c = circumference pi = 3.14 r = radius = 9 inches d = diameter c=pi*d The radius is half of the diameter, d = 2r. Then d = 2*9=18. plug into equation. c= pi*d = 3.14*18 round accordingly and you may want to include that the measurement you end up with is in inches.

leva [86]3 years ago

3 0

56.52 is your answer ....please mark me brainliest

You might be interested in

Pls help for geometry

Alex787 [66]

Answer:20

Step-by-step explana

6 0

3 years ago

Predict: How do you think the formula for area of a triangle will relate to the formula for area of a rectangle? Do you

densk [106]

Answer:

I think is the same formula area .A triangle is half as big as the rectangle that surrounds it, which is why the area of a triangle is one-half base times height.

Step-by-step explanation:

The area of a rectangle is given by the relation length* width. The area of a triangle is given by the relation (1/2)*base* height. Now we know that the two have the same area equal to 150 cm^2. Also, when placed on the same level the tip of the triangle touches the upper edge of the rectangle.

3 0

3 years ago

Find all the solutions for the equation:

Contact [7]

$2y^2\,\mathrm dx-(x+y)^2\,\mathrm dy=0$

Divide both sides by $x^2\,\mathrm dx$ to get

$2\left(\dfrac yx\right)^2-\left(1+\dfrac yx\right)^2\dfrac{\mathrm dy}{\mathrm dx}=0$

$\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{2\left(\frac yx\right)^2}{\left(1+\frac yx\right)^2}$

Substitute $v(x)=\dfrac{y(x)}x$ , so that $\dfrac{\mathrm dv(x)}{\mathrm dx}=\dfrac{x\frac{\mathrm dy(x)}{\mathrm dx}-y(x)}{x^2}$ . Then

$x\dfrac{\mathrm dv}{\mathrm dx}+v=\dfrac{2v^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=\dfrac{2v^2-v(1+v)^2}{(1+v)^2}$

$x\dfrac{\mathrm dv}{\mathrm dx}=-\dfrac{v(1+v^2)}{(1+v)^2}$

The remaining ODE is separable. Separating the variables gives

$\dfrac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=-\dfrac{\mathrm dx}x$

Integrate both sides. On the left, split up the integrand into partial fractions.

$\dfrac{(1+v)^2}{v(1+v^2)}=\dfrac{v^2+2v+1}{v(v^2+1)}=\dfrac av+\dfrac{bv+c}{v^2+1}$

$\implies v^2+2v+1=a(v^2+1)+(bv+c)v$

$\implies v^2+2v+1=(a+b)v^2+cv+a$

$\implies a=1,b=0,c=2$

Then

$\displaystyle\int\frac{(1+v)^2}{v(1+v^2)}\,\mathrm dv=\int\left(\frac1v+\frac2{v^2+1}\right)\,\mathrm dv=\ln|v|+2\tan^{-1}v$

On the right, we have

$\displaystyle-\int\frac{\mathrm dx}x=-\ln|x|+C$

Solving for $v(x)$ explicitly is unlikely to succeed, so we leave the solution in implicit form,

$\ln|v(x)|+2\tan^{-1}v(x)=-\ln|x|+C$

and finally solve in terms of $y(x)$ by replacing $v(x)=\dfrac{y(x)}x$ :

$\ln\left|\frac{y(x)}x\right|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\ln|y(x)|-\ln|x|+2\tan^{-1}\dfrac{y(x)}x=-\ln|x|+C$

$\boxed{\ln|y(x)|+2\tan^{-1}\dfrac{y(x)}x=C}$

7 0

3 years ago

What is the distance between the points?! round to the nearest tenth i need to show work

Maru [420]

Answer:

c= $\sqrt{52}$

Step-by-step explanation:

a=height=6

b=length=4

using pythagorean theorem

a^2+b^2=c^2

36+16=c^2

c= $\sqrt{36+16}$

c= $\sqrt{52}$

6 0

3 years ago

Three times the sum of a number and 2<br> is 7

Ainat [17]

3(x+2)=7 X=1/3 Because 3(x+2) would simplify to 3x+6=7 and then its a two-step equation

8 0

3 years ago

Read 2 more answers