Y^2-y-42 pls helpppppp i dunno how to do this one??

Mathematics

2 answers:

beks73 [17]3 years ago

6 0

(y-7)(y+6)
Hopefully this is right :)

krek1111 [17]3 years ago

6 0

(y-7) (y+6) is the correct answer for this question

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I’m confused can ya help me

Harlamova29_29 [7]

Answer:

C & D

Step-by-step explanation:

x² + 3x - 3 = 0

a = co efficient of x² = 1

b= co efficient of x = 3

c = constant = -3

roots = (-b ± $\sqrt{b-4ac}$ )/2a

= (-3± $\sqrt{3^{2}-4*1*[-3]}$ )/2*1

= (-3± $\sqrt{9+12}$ )/2

= (-3±√21)/2

$x = \frac{-3+\sqrt{21}}{2} ; x =\frac{-3-\sqrt{21}}{2}$

7 0

3 years ago

who does the number, of zeros in the product of 8 and 5000 compara to the number of zeros in the factors ? explain.

mezya [45]

If one of the numbers we multiply (factors) has zeros at the end, and the other isn't a fraction: all those zeros will stay in the product.

But there might be additional zeros if the other numbers in the factors (the numbers which aren't 0) mupliply to "end" in zero and this is the case here:

8*5=40.

so the product will be 40 and the zeros of the 5000:

40 000

the number of zeros in the product will be bigger than the number of zeros in the factors if the non-zero parts of the fractions multiply to a number with 0 at the end.

4 0

3 years ago

In a two-digit number, the tens digit is 5 less than the units digit. The number itself is five more than three times the sum of

Luden [163]

Given:

In a two-digit number, the tens digit is 5 less than the units digit.

The number itself is five more than three times the sum of its digits.

To find:

The number.

Solution:

Let the two digit number is ab. So,

$ab=10a+b$