Me ayudan porfavor no entendí

Mathematics

2 answers:

Rudiy272 years ago

7 0

Answer:

Como puedo ayudar?

Step-by-step explanation:

AlexFokin [52]2 years ago

6 0

¿Qué no entiendes para que pueda ayudarte?

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A printer need to make a poster that will have a total poster area of 200 in^2 and will have 1 inch margins on the sides, a 2-in

Katyanochek1 [597]

Answer:

The dimensions that will give the largest printed area of 132.1669 in^2 are

= Length x Width

= 15.20829 * 8.69045

Step-by-step explanation:

a) Data and Calculations:

Total poster area = 200 in^2

Side margins = 1 inch each

Top and bottom margins = 2 inches each

Let x = length of the full poster

then 200/x = width of the full poster

Therefore, the length of the printed area = x - 3.5

and the width of the printed area = (200/x)-2

Therefore, the Area of the Printed space = (x-3.5)((200/x)-2)

Solving for the Area (A) of the printed space, we have

A = (x-3.5)(-200/x2) + ((200/x)-2)

A = 700 -2x2

If the derivative is set to 0, we have:

0 = 700 -2x2

700 = 2x2

350 = x2

x = 18.70829 The original length

width = 10.69045

Therefore, the area of space available for printing is

15.20829 * 8.69045

= 132.1669 in^2

5 0

2 years ago

circle a has a radius of 7 and arcs rc cs and sm are congruent to the nearest hundereth what is the length of arc rc

oksian1 [2.3K]

The complete question in the attached figure

we know that
[arcs rc +arc cs arc sm]---------------> they take up half a circle-------->180°
 they are all congruent
so
divide 180 by 3 ----------------> 180/3=60°

Find the length of arc rc=60°

if 360°----------------> (2*pi*7) length of circumference
60° -------------------> X
X=60*2*pi*7/360------------> 7.327 units

the answer is
the length of arc rc= 7.33 units