I think it’s 6 but i’m not sure
Since the width is the smaller value, make the width=x. That would make the length=2x-3. Area=length*width. Substitute your variables and known values into the equation. 14=(2x-3)(x). Distribute the x to give you
![14=2 x^{2} -3x](https://tex.z-dn.net/?f=14%3D2%20x%5E%7B2%7D%20-3x)
. Set the equation equal to 0 giving you
![2 x^{2} -3x-14=0](https://tex.z-dn.net/?f=2%20x%5E%7B2%7D%20-3x-14%3D0)
. Factor the equation to give you
![(2x-7)(x+2)=0](https://tex.z-dn.net/?f=%282x-7%29%28x%2B2%29%3D0)
. Set each factor equal to 0 and solve. 2x-7=0 gives you x=7/2 & x+2=0 gives you x=-2. Since we're working with lengths and widths, the answer cannot be negative. Therefore, your width equals 7/2. To find the length, substitute 7/2 into the original expression for length (2x-3). That gives you 2*(7/2)-3=7-3=4. The length is 4.
Last one for sure, the others im not too sure about