Factorize the polynomial: 6q^2 – q – 12.
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We'll have this following figure drawn in the picture. Since we have an isosceles trapezoid, the diagonals are congruent. According to the conditions of the problem, these diagonals are perpendicular and then we can claim that we'll have right-isosceles triangles in this case. Indeed, ∠OBC = ∠FBD = 45°. Then, in the triangle BFD. BF=FD=23. It means the height is 23 cm. Obtaining this fact, we can easily calculate the area. 
