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ollegr [7]
3 years ago
13

Factorize the polynomial: 6q^2 – q – 12.

Mathematics
1 answer:
Ksivusya [100]3 years ago
8 0

Answer:

Step-by-step explanation:

What two number multiply to equal 6*(-12) and add to equal -1? That is -9 and +8.

6q^2-9q+8q-12

Now factor by grouping

(6q^2-9q)+(8q-12)\\3q(2q-3)+4(2q-3)\\(3q+4)(2q-3)

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Solve for x and explain the steps:<br> 3x-6=4(2-3x)-8x
mote1985 [20]

Answer: x = 14/23

Step-by-step explanation:

3x-6=4(2-3x)-8x

3x-6=8-12x-8x --> Expand 4(2-3x)

3x-6=8-20x --> Collect like terms

3x-6+6=8-20x+6 --> Add 6 to both sides, to remove it from the right side

3x=-20x+14

3x+20x=-20x+14+20x --> Add 20x to both sides, to remove it from the left side

23x=14

\frac{23x}{23}=\frac{14}{23} --> Divide both sides by 23

x = 14/23

7 0
2 years ago
What is the solution to the equation?<br> 2<br> a+53 =<br> =9
Andre45 [30]

Answer:

-22

Step-by-step explanation:

8 0
4 years ago
How does the method for solving equations with fractional or decimal coefficients and constants compare with the method for solv
I am Lyosha [343]

Answer:

Step-by-step explanation:

When solving equations with fractional or decimal coefficients, the equations needs to be multiplied by the multiple of denominator such that the equations have integer coefficients and constants

6 0
3 years ago
Help me to answer this question pl​s
attashe74 [19]

Problem 1

Draw a straight line and plot P anywhere on it. Use the compass to trace out a faint circle of radius 8 cm with center P. This circle crosses the previous line at point Q.

Repeat these steps to set up another circle centered at Q and keep the radius the same. The two circles cross at two locations. Let's mark one of those locations point X. From here, we could connect points X, P, Q to form an equilateral triangle. However, we only want the 60 degree angle from it.

With P as the center, draw another circle with radius 7.5 cm. This circle will cross the ray PX at location R.

Refer to the diagram below.

=====================================================

Problem 2

I'm not sure why your teacher wants you to use a compass and straightedge to construct an 80 degree angle. Such a task is not possible. The proof is lengthy but look up the term "constructible angles" and you'll find that only angles of the form 3n are possible to make with compass/straight edge.

In other words, you can only do multiples of 3. Unfortunately 80 is not a multiple of 3. I used GeoGebra to create the image below, as well as problem 1.

8 0
2 years ago
Will mark brainliest if correct. Find what the measurement of angles a-d are and state the reason
Furkat [3]

Answer: D = 70  

              A = 30

Explanation: d is parallel to 70 degrees, 40 is parallel to e, and the whole set of angles is 180 so 180 - 2(70) + 2(40)  = 30 so D = 70 and A = 30

7 0
3 years ago
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