Answer:
a) The genotype of her father = "aa".
The genotype of her mother = "Aa".
The genotype of Sally is "Aa".
b) 1/2
c) 1/2
Explanation:
a) Sally's father has alkaptonuria. So, the genotype of her father is "aa". Her mother is normal. Since her brother is affected by the disease, he should be homozygous recessive (aa). This means that the mother also has one copy of "a" allele and is heterozygous dominant (Aa). A cross between Aa (mother) and aa (father) would give 50% affected progeny with "Aa" genotype. So, the genotype of Sally is "Aa".
b) The genotype of her mother= Aa
The genotype of her father = aa
Aa x aa = 1/2 Aa (affected): 1/2 aa (normal)
So, if Sally's parents have another child, there is a 1/2 probability that this child will have alkaptonuria.
c) The genotype of Sally = Aa
Genotype of the man Sally marries= aa (since he is affected with alkaptonuria)
Aa x aa= 1/2 Aa (affected): 1/2 aa (normal)
There is a 1/2 probability that their child will have alkaptonuria.
The correct answer is A. B might sound like it is right but that has nothing to do with what the question is asking. And C is not correct because under the the temperature is 4 degrees c.
Answer:
The options are:
A. operant conditioning
B. classical conditioning
C. innate behavior
D. imprinting
E. altruistic behavior
The correct answer is A. operant conditioning.
Explanation:
The rat's behavior is learned, an example of conditioned behavior.
In operant conditioning, the behavior is committed to memory via the adoption of reward or punishment. In these case study, the rat conditioned behavior is to manoeuvre the maze to get its reward: food.
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Here is the full question
Listed are several examples of types of animal behavior. Choose the letter of the correct term (A-E) that matches each example in the following questions. operant conditioning classical conditioning innate behavior imprinting altruistic behavior Through trial and error, a rat learns to run a maze without mistakes to receive a food reward.
