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Anna007 [38]
3 years ago
12

∠LMN and ∠NMO are a linear pair of angles. If ∠LMN = 4x + 3 and ∠NMO = 10x – 5, then find the value of x. (1 point)

Mathematics
2 answers:
andriy [413]3 years ago
8 0
Linear angles are two angles that are part of a straight angle (180*), so both must add up to 180.   If 4x+3+10x-5+180, then 14x-2=180, then 14x=182, and x=13
OLEGan [10]3 years ago
6 0

Answer: x = 13


Step-by-step explanation:

Given: ∠LMN and ∠NMO are a linear pair of angles.

We know that linear pair of angles are supplementary.

Then ∠LMN + ∠NMO=180°

If ∠LMN = 4x+3 and ∠NMO = 10x-5,

\Rightarrow4x+3+10x-5=180

\Rightarrow14x-2=180\\\Rightarrow14x=180+2\\\Rightarrow14x=182\\\Rightarrow\ x=\frac{182}{14}\\\Rightarrow\ x=13

Hence, the value of x=13 .


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In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

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Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

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