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Dafna11 [192]
3 years ago
12

Is this right? Will mark branliest for the correct answer

Mathematics
2 answers:
wolverine [178]3 years ago
7 0
It’s the first one :)
horsena [70]3 years ago
6 0

Answer:

No

Step-by-step explanation:  

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What is the answer to this
Vika [28.1K]

Answer:

The upper one is 8, the lower one is 6

7 0
3 years ago
There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
3 years ago
Two over twenty-two plus six over eleven
kirill [66]

\frac{2}{22}+\frac{6}{11}


Simplify \frac{2}{22} to \frac{1}{11}


\frac{1}{11}+\frac{6}{11}


Both are over 11, so, just sum.


\frac{1+6}{11}

\frac{7}{11}

4 0
3 years ago
Read 2 more answers
Logariths, please help​
Valentin [98]

Answer:

<em>{ - 2 , 8 } </em>

Step-by-step explanation:

log_{4} ( x² - 6x ) = 2

4² = ( x² - 6x )

x² - 6x - 16 = 0

- 6 = - 8 + 2

- 16 = - 8 * 2

( x - 8 )( x + 2 ) = 0 ⇒ x_{1} = - 2 , x_{2} = 8

<em>{ - 2 , 8 }</em>

3 0
2 years ago
When variables are being raised to a power what operation is performed with the exponents?
Ludmilka [50]

First you raise the expressions in the parentheses to their powers. Then multiply the two expressions together. You get to see multiplying exponents (raising a power to a power) and adding exponents (multiplying same bases).

4 0
3 years ago
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