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iVinArrow [24]
3 years ago
12

23 20' 48" is the same as _____. Round to the nearest hundredth of a degree.

Mathematics
1 answer:
boyakko [2]3 years ago
8 0
So this is read as 23 degrees, 20 minutes, and 48 seconds.  Each degree has 60 minutes and each minute has 60 seconds, somewhat like time.  You must start from right to left for this to work.  This may seem complicated but the way to find this is as follows:  
23+(20+(48/60))/60.  A simpler way to see this is by first taking 48/60 which is .8.  Now you take 20+.8 which is 20.8 and you divide it by 60 once more.  This comes out to be approximately .35.  Now you have converted the seconds and minutes to degrees so you add 23+.35 which is 23.35.  Therefore your answer is 23.35 degrees.  
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4x + 7y - 6z + 6y - 9x<br> 4x and ___ are like terms<br> 7y and ___ are like terms
solmaris [256]

Answer:

the answer is -5x + 13y - 6z

6 0
2 years ago
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Find one solution for the equation. Assume that all angles involved are acute angles.
Nikitich [7]

9514 1404 393

Answer:

  B = 13

Step-by-step explanation:

The tangent and cotangent are equal when the angles are complementary.

  (3B +35) +(2B -10) = 90

  5B = 65

  B = 13

___

<em>Check</em>

For B=13, the angles are 3B+35 = 39+35 = 74, and 2B-10 = 26-10 = 16. Both are acute angles.

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3 years ago
The life in hours of a biomedical device under development in the laboratory is known to be approximately normally distributed.
tatuchka [14]

Answer:

a)Null hypothesis:- H₀: μ> 500

  Alternative hypothesis:-H₁ : μ< 500

b) (5211.05 , 5411.7)

95% lower confidence bound on the mean.

c) The test of hypothesis t = 5.826 >1.761 From 't' distribution table at 14 degrees of freedom at 95% level of significance.

Step-by-step explanation:

<u>Step :-1</u>

Given  a random sample of 15 devices is selected in the laboratory.

size of the small sample 'n' = 15

An average life of 5311.4 hours and a sample standard deviation of 220.7 hours.

Average of sample mean (x⁻) =  5311.4 hours

sample standard deviation (S) = 220.7 hours.

<u>Step :- 2</u>

<u>a) Null hypothesis</u>:- H₀: μ> 500

<u>Alternative hypothesis</u>:-H₁ : μ< 500

<u>Level of significance</u> :- α = 0.95 or 0.05

b) The test statistic

t = \frac{x^{-} - mean}{\frac{S}{\sqrt{n-1} } }

t = \frac{5311.4 - 500}{\frac{220.7}{\sqrt{15-1} } }

t = 5.826

The degrees of freedom γ= n-1 = 15-1 =14

tabulated value t =1.761 From 't' distribution table at 14 degrees of freedom at 95% level of significance.

calculated value t = 5.826 >1.761 From 't' distribution table at 14 degrees of freedom at 95% level of significance.

Null hypothesis is rejected at  95% confidence on the mean.

C) <u>The 95% of confidence limits </u>

(x^{-} - t_{0.05} \frac{S}{\sqrt{n} } ,x^{-} + t_{0.05}\frac{S}{\sqrt{n} } )

substitute values and simplification , we get

(5311.4 - 1.761 \frac{220.7}{\sqrt{15} } ,5311.4 +1.761\frac{220.7}{\sqrt{15} } )

(5211.05 , 5411.7)

95% lower confidence bound on the mean.

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astra-53 [7]

Answer: well 56 is the answer

Step-by-step explanation:

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y = 0.72 - 3x/11
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