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3 years ago

12

23 20' 48" is the same as _____. Round to the nearest hundredth of a degree.

1 answer:

boyakko [2]3 years ago

8 0

So this is read as 23 degrees, 20 minutes, and 48 seconds. Each degree has 60 minutes and each minute has 60 seconds, somewhat like time. You must start from right to left for this to work. This may seem complicated but the way to find this is as follows:
23+(20+(48/60))/60. A simpler way to see this is by first taking 48/60 which is .8. Now you take 20+.8 which is 20.8 and you divide it by 60 once more. This comes out to be approximately .35. Now you have converted the seconds and minutes to degrees so you add 23+.35 which is 23.35. Therefore your answer is 23.35 degrees.

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How many times do you need to regroup to add 873+465

lukranit [14]

1.87741935484 to be exact

3 0

2 years ago

A submarine lies 3 kilometers from the path of a target ship. The sub’s torpedoes have a range of 5 kilometers. For what distanc

aev [14]

The distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

Explanation:

The submarine lies 3 km from the target ship.

Let B denotes the target ship and C denotes the submarine.

Let AC denotes the the target ship would be within the range of the torpedoes.

The image attached below illustrates that the distance between submarine and the target ship and the range of the torpedoes.

Let BC denotes the distance between the target ship and the submarine. Let AC denotes the range of the torpedoes.

To determine the length of AB, let us use Pythagorean theorem,

$AC^{2} =AB^{2} +BC^{2}$

Substituting the values of BC = 3 and AC = 5, we have,

$5^{2} =AB^{2} +3^{2}$

Squaring the terms, we get,

$25 =AB^{2} +9$

Subtracting both sides by 9, we have,

$16 =AB^{2}$

Taking square root on both sides,

$AB = 4$

Thus, the distance along the path of the ship be within the range of the torpedoes is 4 kilometers.

5 0

3 years ago

larisa86 [58]

Answer:

see below

Step-by-step explanation:

f(x) = 5x^3 +1, g(x) = – 2x^2, and h(x) = - 4x^2 – 2x +5

f(-8) = 5(-8)^3 +1 = 5 *(-512) +1 =-2560+1 =-2559

g( -6) = -2 ( -6) ^2 = -2 ( 36) = -72

h(9) = -4( 9)^2 -2(9) +5 = -4 ( 81) -18+5 = -324-18+5=-337

3 0

3 years ago

Read 2 more answers

The main sail of a sailboat has the dimensions shown in the figure at the right. What is the height of the main sail?

levacccp [35]

Answer:

$h = 16.1$

Step-by-step explanation:

$sin A /a = sin B / b = sin C/c$ where A is angle and a is side opposite of angle

$sin (49) / h = sin(41)/ 14$ cross-multiply

$h*sin(41) = 14 * sin(49)$

$h = (14*sin(49))/ sin(41)$

$h = 16.1$

5 0

2 years ago

Please please please help

grin007 [14]

Answer:

hello, i don't know what is answer, beacose im Ukrainian, sorry

8 0

2 years ago