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2 years ago

PLEASE HELP WITH THESE 2

Mathematics

1 answer:

Salsk061 [2.6K]2 years ago

5 0

Answer:

1. ?=100 2.?=70

Step-by-step explanation:

1. for the inner arch, you just have to multiply by 2 so 50x2

2. to find the inner arch from the outer arch, you have to divide by two so 140/2

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¿cuáles son los criterios de congruencia y semejanza de triángulo?

mars1129 [50]

Answer:

Two triangles are similar if they meet one of the following criteria. : Two pairs of corresponding angles are equal. : Three pairs of corresponding sides are proportional. : Two pairs of corresponding sides are proportional and the corresponding angles between them are equal.

Dos triángulos son similares si cumplen uno de los siguientes criterios. : Dos pares de ángulos correspondientes son iguales. : Tres pares de lados correspondientes son proporcionales. : Dos pares de lados correspondientes son proporcionales y los ángulos correspondientes entre ellos son iguales.

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A cylindrical tin can for cookies has a height of 6 inches and a radius of 2 inches. What is the volume of the tin can? Use 3.14

Anna007 [38]

Answer:

The answer is 75.4

Step-by-step explanation:

I hope it helps

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2 years ago

PLEASEEEE HELPPP MEEEE! NOWWWWW

umka2103 [35]

Answer:

The answer is -3

Step-by-step explanation:

First of all we find the difference -4-2 = -(4+2) and than we add the numbers answer is -6 .

$- \frac{6}{4 \div 2}$

4÷2=

$- \frac{6}{2}$

And than we simplify this fraction to 2 and find the answer -3. I would be glad if you choose my answer the best. Good lessons ♡

7 0

2 years ago

The product of a positive number and 2 more than that number is 63 find the numbers

Kobotan [32]

I really don't know how toowrk it out on paper, I'm afraid. I just looked at it, and somehow knew that the answers are 7 and 9.

6 0

2 years ago

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

mixer [17]

Notice the picture below

x = 1 and y = -1

now... recall your SOH CAH TOA $\bf sin(\theta)=\cfrac{y}{r}
\qquad 
% cosine
cos(\theta)=\cfrac{x}{r}
\qquad 
% tangent
tan(\theta)=\cfrac{y}{x}$

now.. what's the value for "r" or the radius? well, using the pythagorean theorem $\bf c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\qquad 
\begin{cases}
a=x\\
b=y\\
c=r
\end{cases}$

6 0

3 years ago