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3 years ago

Factor completely. a 2 + 28a + 27

Mathematics

2 answers:

riadik2000 [5.3K]3 years ago

6 0

A² + 28a + 27 =
a² + a + 27a + 27 =
a(a + 1) + 27(a + 1) =
(a + 27)(a + 1)

Lilit [14]3 years ago

5 0

<span>a^2 + 28a + 27
=(a+27)(a+1)

hope it helps</span>

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As part of quality-control program, 3 light bulbs from each bath of 100 are tested. In how many ways can this test batch be chos

hichkok12 [17]

Answer:

<h3>By 161700 ways this test batch can be chosen.</h3>

Step-by-step explanation:

We are given that total number of bulbs are = 100.

Number of bulbs are tested = 3.

Please note, when order it not important, we apply combination.

Choosing 3 bulbs out of 100 don't need any specific order.

Therefore, applying combination formula for choosing 3 bulbs out of 100 bulbs.

$^nCr = \frac{n!}{(n-r)!r!}$ read as r out of n.

Plugging n=100 and r=3 in above formula, we get

$^100C3 = \frac{100!}{(100-3)!3!}$

Expanding 100! upto 97!, we get

= $\frac{100\times 99\times 98\times 97!}{97!3!}$

Crossing out common 97! from top and bottom, we get

= $\frac{100\times 99\times 98}{3!}$

Expanding 3!, we get

= $\frac{100\times 99\times 98}{3\times 2\times 1}$

= 100 × 33 × 49

= 161700 ways.

<h3>Therefore, by 161700 ways this test batch can be chosen.</h3>

3 0

4 years ago

What is the equation of the

Leya [2.2K]

Answer:

y = 2x - 1

Step-by-step explanation:

Here we have the slope, m = 2, and one point on the line, (2, 3). Plugging these values into the point-slope formula y - k = m(x - h), we get:

y - 3 = 2(x - 2), or y = 3 + 2x - 4, or y = 2x - 1 in slope-intercept form.

8 0

3 years ago

HELLPPP <br> I need help asappp

sattari [20]

Answer:

(8,5)

Step-by-step explanation:

x=8

5*8-2y=30

40-2y=30 . subtract 40 from both sides

-2y=-10 . divide both sides by-2

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3 years ago

WILL MARK BRAINLIEST PLEASE HELP

Llana [10]

The answer is : y= 2x+4

3 0

3 years ago

The expression p/x^2 - 5x +6 simplifies to x+4/x-2. Which expression doees p represent?

gladu [14]

We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d

we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor

p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)

therefor
p=d(x+4) and
x^2-5x+6=d(x-2)

we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub

p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
$p= \frac {(x-6)(x+1)(x+4)}{(x-2)}$

7 0

3 years ago