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zysi [14]
3 years ago
5

Need help please urgent. Correct answers only no links.

Mathematics
1 answer:
vlabodo [156]3 years ago
8 0

Answer:

the exact answer is 314.159265359

Step-by-step explanation:

but it simplifies to 314.16

You might be interested in
!
Darina [25.2K]

The graph of the equations was plotted using geogebra graphing and attached.

Let x represent the hours weightlifting and y represent the hours doing cardio exercises.

Since he spend a maximum of 20 hours, hence:

x + y ≤ 20   (1)

Also, he spends at least 8 of those hours weightlifting, hence:

x ≥ 8          (2)

He wants to spend no more than 15 hours doing cardio exercises, this is:

y ≤ 15     (3)

The graph of the equations was plotted using geogebra graphing and attached.

Find out more at: brainly.com/question/17178834

3 0
3 years ago
1 2 3 4 5 6 7 8 9 10 TIME REMAINING 52:51 Use the data set to determine which statements are correct. Check all that apply. 35,
Nady [450]

Answer:

The true statements are:

  • The median is 38.5.
  • There is an outlier.
  • The lower quartile is 29.
  • The upper quartile is 70.
  • The interquartile range is 41.

Step-by-step explanation:

The given data are:  35, 41, 18, 75, 36, 21, 62, 29, 154, 70

Make the data in order from the least to the greatest

18 , 21 , 29 , 35 , <u>36 , 41</u> , 62 , 70 , 75 , 154

So, the median of the data = (36 + 41)/2 = 38.5

We can deduce that The number 154 represents an outlier because the difference between 154 and 75 is much greater than the difference between the other data

If we divided the data to two groups , they will be:

(18 , 21 , <u>29 </u>, 35 , 36)  ,  (41 , 62 , <u>70 </u>, 75 , 154)

So, The lower quartile Q1 is the median of the first group = 29

And the upper quartile Q2 is the median of the second group = 70

And the interquartile range = Q2 - Q1 = 70 - 29 = 41

So, the true statements are:

  • The median is 38.5
  • There is an outlier
  • The lower quartile is 29
  • The upper quartile is 70
  • The interquartile range is 41.
7 0
3 years ago
What is the effect on the graph of f(x) = x2 when it is transformed to h(x) = 2 x2 + 15?
kirill [66]

Answer:

B

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Identify the percent of change as increase or decrease of 138 to 75
RUDIKE [14]
138 x ? = 75
? = 75/138 = 0.544(3sf)
so about 54.35% (2dp) decrease
8 0
3 years ago
In 1990, 1000 adults were randomly selected and each was asked if they smoked, 300
Oduvanchick [21]

Answer:

 The proportion of smokers was higher in 1990 than in 2000

Step-by-step explanation:

Solution

Recall that,

The total number of sample 1 (n1) = 1000

Total  sample 2 number  (n2) = 2000

The number of favourable events (X1) = 300

The number of favourable events (X2) = 500

so,

p₁ = X₁/n₁ = 300/1000 = 0.3

p₂ = X₂/n₂ =500/2000 =0.25

α = 0.05

We are interested in testing the hypothesis.

The  hypothesis (Null) ....>  H₀ : p₁ = p₂

Alternate hypothesis------ > H₁ : p₁ > p₂

Thus,

P = X₁ + X₂/ n₁ + n₂

P =300 + 500/1000 +2000

P =800/3000

=0.2667

Now,

Z₀ = P₁ - P₂/√ P (1 -P) (1/n₁ + 1/n₂)

Z₀ =  0.3 - 0.25/√0.2667  (1 - 0.2667) (1/1000 + 1/2000)

Z₀ = 0.4999999999999999/√ 0.2667 (0.7333000000000001) (0.001 +0.0005)

Then,

Z₀ = 0.4999999999999999/√0.00029335666500000004

Z₀ = 2.9193

so,

zα/2 = z0.05/2 =z0.025

zα/2 = 1.6448536269514722

Now, we apply the decision rule:

Decision Rule: Reject the null hypothesis if the statistic value test is higher than the critical value 1.6448536269514722

The statistic value, 2.9193 is greater than the critical value 1.6448536269514722,  then we will reject the null hypothesis.

Therefore, the proportion of smokers was higher in 1990 than in 2000

3 0
3 years ago
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