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kap26 [50]
3 years ago
7

PLease help i think it is c

Mathematics
1 answer:
Zanzabum3 years ago
7 0

Answer:

a, b and c

Step-by-step explanation:

in my opinion, I think its a, b and c...

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You need to buy new soil for your garden. Find the area of the garden. Use the dimensions shown in the picture.
Lubov Fominskaja [6]

Answer:

95 square meters

Step-by-step explanation:

I am answering this question assuming 19 is the base because it is the longest side on the triangle. (there is no picture provided)

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3 0
2 years ago
If g(x) = 4x + 1 and g(x) = -11, find x.
podryga [215]

Answer:

x = - 3

Step-by-step explanation:

g(x) = 4x + 1...... (1)

g(x) = -11.... (2)

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3 years ago
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tigry1 [53]

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68

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Find two consecutive odd integers whose product is 323
Harrizon [31]
Use a let statement 
first
let x and x + 2 be the number so you write it like this
<u>let x = the first consecutive integer
</u><u>let x + 2 = the second consecutive integer
</u>
second
x(x+2)=323
x^2 + 2x = 323
        -323  -323
x^2 + 2x -323 = 0

third
try to factor -323 so it is 19 and -17
(x + 19) (x - 17) = 0
x = 19 
x = -17

hope this help

4 0
3 years ago
[Geometry Basics] I'm just checking if this is correct:
Leno4ka [110]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }&#10;\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ x &,& y~) &#10;%  (c,d)&#10;&&(~ -9 &,& -1~)&#10;\end{array}\qquad&#10;%   coordinates of midpoint &#10;\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)&#10;\\\\\\&#10;\left( \cfrac{-9+x}{2}~~,~~\cfrac{-1+y}{2} \right)=\stackrel{midpoint}{(8,14)}\implies &#10;\begin{cases}&#10;\cfrac{-9+x}{2}=8\\\\&#10;-9+x=16\\&#10;\boxed{x=25}\\&#10;-------\\&#10;\cfrac{-1+y}{2} =14\\\\&#10;-1+y=28\\&#10;\boxed{y=29}&#10;\end{cases}

\bf -------------------------------\\\\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&&(~ x &,& y~) &#10;%  (c,d)&#10;&&(~10 &,& 12~)&#10;\end{array}\qquad&#10;\\\\\\&#10;\left( \cfrac{10+x}{2}~~,~~\cfrac{12+y}{2} \right)=\stackrel{midpoint}{(6,9)}\implies &#10;\begin{cases}&#10;\cfrac{10+x}{2}=6\\\\&#10;10+x=12\\&#10;\boxed{x=2}\\&#10;-------\\&#10;\cfrac{12+y}{2} =9\\\\&#10;12+y=18\\&#10;\boxed{y=6}&#10;\end{cases}
3 0
3 years ago
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