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anygoal [31]
3 years ago
6

2ax-b=cx+d solve for x​

Mathematics
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

x = (d + b) / (2a - c)

Step-by-step explanation:

2ax-b = cx+d

2ax - cx = d + b

x (2a-c) = d + b

x = (d + b) / (2a - c)

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Carla has 1 gallon of paint. She is going to pour it into a paint tray that measures 10 inches wide, 10 inches long, and 7 cm de
STatiana [176]
To determine the correct statement in the choices presented, we first have to solve the area of the tray. We assume it to be in a rectangular form so the area is:

Area = 10 in x 10 in x 7/2.54 in = 275.59 in³ for the paint tray
1 gallon paint = 231 in³ paint

Therefore, the correct answer is the first option. <span>The paint will not fill the tray by 44.59 in</span>³<span>.</span>
7 0
3 years ago
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PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The
Nookie1986 [14]
<h3><u>Answer:</u></h3>

\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}

<h3><u>Step-by-step explanation:</u></h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

  • Radius of smaller circle be r .
  • Radius of smaller circle be r .
  • Area of shaded region be \bf Area_{shaded}

\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2  \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2)  \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2]  \\\\\bf\implies Area_{shaded}  = \pi [ 100cm^2-16cm^2]  \\\\\bf\implies Area_{shaded}  = \pi \times 84cm^2  \\\\\bf\implies Area_{shaded}  = \dfrac{22}{7}\times 84cm^2  \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}

<h3><u>Hence </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> the</u><u> </u><u>shaded </u><u>region</u><u> is</u><u> </u><u>2</u><u>6</u><u>4</u><u> </u><u>cm²</u><u>.</u></h3>

5 0
3 years ago
Isabel will rent a car for the weekend. She can choose one of two plans. The first plan has an initial fee of $46 and costs an a
zaharov [31]

The missing part of the question is "For what amount of driving do the two plans cost the same"

The amount of driving that do the two plans cost the same is 450 miles

Step-by-step explanation:

Isabel will rent a car for the weekend. She can choose one of two plans

  • The first plan has an initial fee of $46 and costs an additional $0.13 per mile driven
  • The second plan has an initial fee of $55 and costs an additional $0.11 per mile driven

We need to find for what amount of driving do the two plans cost the same

Assume that she will drive for d miles

The first plan:

∵ The initial fee is $46

∵ The additional cost is 0.13 per mile

∵ She will drive for d miles

- The cost of her trip is the sum of $46 and the product of

   0.13 and d

∴ The cost = 46 + 0.13 d ⇒ (1)

The second plan:

∵ The initial fee is $55

∵ The additional cost is 0.11 per mile

∵ She will drive for d miles

- The cost of her trip is the sum of $55 and the product of

   0.11 and d

∴ The cost = 55 + 0.11 d ⇒ (2)

∵ The cost of the two plans is the same

- Equate (1) and (2) to find d

∴ 46 + 0.13 d = 55 + 0.11 d

- Subtract 46 from both sides

∴ 0.13 d = 0.11 d + 9

- Subtract 0.11 d from both sides

∴ 0.02 d = 9

- Divide both sides by 0.02

∴ d = 450

The amount of driving that do the two plans cost the same is 450 miles

Learn more:

You can learn more about the word problems in brainly.com/question/3950386

#LearnwithBrainly

5 0
4 years ago
Is 5/8 bigger or smaller than 4/6<br>is -3/2 bigger or smaller than -4/6
Mashutka [201]
\frac{5}{8} ....\frac{4}{6} \\\\ \frac{15}{24} < \frac{16}{24} \\\\\\ -\frac{3}{2} ....-\frac{4}{6} \\\\ -\frac{9}{6} < -\frac{4}{6}


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The function f(a) 260 - 55x represents the distance, in miles, remaining on a trip x hours
belka [17]

Answer:

260 - 55(3)

55(3)

260 - 165

= 95

Step-by-step explanation:

8 0
3 years ago
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