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Paul [167]
3 years ago
14

Find the angle of rotation about the center of the square that maps A to C.

Mathematics
1 answer:
zheka24 [161]3 years ago
5 0

Answer:

Step-by-step explanation:270 ez

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Is (1,6) a solution to the inequality 3x + 5y > 14
andrew-mc [135]

Answer:

No

Step-by-step explanation:

Check this out by subbing 1 for x and 6 for y in the given inequality:

3(1) + 5(6) > 14.  We must determine whether this is true or not.

3 + 30 > 14 is false, so no, (1, 6) is not a solution to this inequality.

3 0
3 years ago
POSSIBLE POINTS: 4 The length of a rectangle is 4 inches more than the width. The area of the rectangle is 45 in2 Find the lengt
EleoNora [17]

Answer:

x (x + 4) = 45

x^2 + 4x - 45 = 0

factor

(x + 9)(x - 5) = 0

x = -9 or 5

 

your length cannot be negative so x= 5 and x+4 =9

Step-by-step explanation:

Hope this answer is Wright

4 0
3 years ago
Find the square root 64/100
Papessa [141]
Answer: 4/5

Step by Step:

5 0
3 years ago
A cone is cut into a cube as shown below. If the cone has a diameter of
Butoxors [25]

Answer:

184.43in².

Step-by-step explanation:

Total surface area of the solid = volume of the cube - the volume of the cone

For the CUBE;

Volume of the cube = L³ where L is the length of one side of the cube.

Since a cone of diameter of 6in is cut into a cube, then the length of the cube will be 6in.

Volume of the cube = 6³ = 216in³

For the CONE;

Volume of the cone = 1/3 πr²h

r is the radius of the cone = diameter/2

r = 6/2 = 3in

slant height l = 4.5in

the height h of the cone will be derived using the Pythagoras theorem.

l² = h²+r²

4.5² = h²+3²

h² = 4.5²-3²

h² = 11.25

h=√11.25

h = 3.35in

Volume of the cone = 1/3 × π × 3²× 3.35

= 31.57in³

Total surface area of the solid = 216in³-31.57in³

= 184.43in²

3 0
3 years ago
David made a class banner out of a large rectangular piece of paper. He
spin [16.1K]

<u>Given:</u>

A triangular piece is cut out of a rectangular piece of paper to make the class banner.

<u>To find:</u>

The area of the class banner.

<u>Solution:</u>

The rectangular piece of paper is 14 inches long and 5+3=8 inches wide.

From the given diagram, the triangle has a base length of the same 8 inches and has a height of 14-11=3 inches long.

To determine the area of the banner, we subtract the area of the triangle from the area of the rectangle.

The area of a triangle = \frac{1}{2} (b)(h).

The area of the triangle = \frac{1}{2} (8)(3) = 12 square inches.

The area of a rectangle = (l)(w).

The area of the rectangle = (14)(8)= 112 square inches.

The area of the class banner = 112-12=100 square inches.

So the banner has an area of 100 square inches which is the first option.

7 0
3 years ago
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