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mafiozo [28]
2 years ago
8

HELP , this is the work

Mathematics
1 answer:
34kurt2 years ago
8 0

Answer:

The second step is wrong. It should be -6y =12 so y-intercept is -2

Step-by-step explanation:

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The hypotenuse of a right triangle has endpoints A(4, 1) and B(–1, –2).
zavuch27 [327]

Answer:

(–1, 1)

(4, –2)

Step-by-step explanation:

Let

(x,y) ----> the coordinates of point C

Applying the Pythagoras Theorem

(-1-4)^2+(-2-1)^2=(x-4)^2+(y-1)^2+(x+1)^2+(y+2)^2

step 1

Find the possibles values of x

(-1-4)^2=(x-4)^2+(x+1)^2\\\\25=x^{2}-8x+16+x^{2}+2x+1\\\\2x^{2}-6x-8=0

Simplify

x^{2}-3x-4=0

Solve the quadratic equation

x^{2}-3x-4=(x+1)(x-4)

The values of x are

x=-1 and x=4

step 2

Find the possibles values of y

(-2-1)^2=((y-1)^2+(y+2)^2\\\\9=y^{2}-2y+1+y^{2}+4y+4\\\\2y^{2}+2y-4=0

Simplify

y^{2}+y-2=0

Solve the quadratic equation

y^{2}+y-2=(y+2)(y-1)

The values of y are

y=-2, y=1

therefore

The possibles coordinates of point C are

(-1,1),(4,-2)

3 0
3 years ago
Read 2 more answers
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