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Amanda [17]
3 years ago
13

Product of two numbers is -216. If one of the number is 12, find the other number

Mathematics
1 answer:
vazorg [7]3 years ago
5 0

\huge\boxed{-18}

We know that xy=-216, where x and y are the two numbers.

We know that one of the numbers, x, is equal to 12.

12y=-216

We need to find the value of y. To do so, we must isolate it. In this case, we can isolate y by dividing both sides of the equation by 12.

y=\boxed{-18}

Now, let's check our answer. If we multiply the two factors together, we should get a product of -216.

12*(-18)=-216

-216=-216\ \ \huge\checkmark

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<h3>How to calculate the fraction?</h3>

From the information, Jonah used 1 1/2 cups of brown sugar and 2 1/3 cups for flour.

Therefore, the cups of sugar needed will be:

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2 years ago
Expand<br> (2x - 3)4 <br><br> Can you help me expand this by using the binomial theorem?
saw5 [17]

The value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

<h3>How to expand the expression?</h3>

The expression is given as:

(2x -3)^4

Using the binomial expansion, we have:

(2x -3)^4 = ^4C_0 * (2x)^4 * (-3)^0 +^4C_1 * (2x)^3 * (-3)^1 + ^4C_2 * (2x)^2 * (-3)^2 + ^4C_3 * (2x)^1 * (-3)^3 + ^4C_4 * (2x)^0 * (-3)^4

Evaluate the combination factors.

So, we have:

(2x -3)^4 = 1 * (2x)^4 * (-3)^0 + 4 * (2x)^3 * (-3)^1 + 6 * (2x)^2 * (-3)^2 + 4 * (2x)^1 * (-3)^3 + 1 * (2x)^0 * (-3)^4

Evaluate the exponents and the products

(2x -3)^4 = 16x^4  + 96x^3  +216x^2 -216x + 81

Hence, the value of expanding (2x -3)^4 is 16x^4  + 96x^3  +216x^2 -216x + 81

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