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natka813 [3]
3 years ago
15

Can someone help me with these problems

Mathematics
2 answers:
galina1969 [7]3 years ago
4 0

Answer:

a.2

b.2

c.3x

a.3(x+2)

b.-(2-x)

c.3x-2

Paraphin [41]3 years ago
3 0

Answer:

a.3x+6=3 (x+2)

b.x-2=-(2-x)

15x-10/5=3x-2

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Find the solution to the equation <br> 3x + 1 = 6x + 1
Musya8 [376]

Answer:

x=0

Step-by-step explanation:

First, start by getting rid of your X values. You must take your lowest X value and find a way to move it to the other side. Our lowest X value is 3x, and it's currently being added to 1.

In order to move it, we must subtract it on both sides.

3x + 1 = 6x + 1

-3x        -3x

1 = 3x + 1

Now we must get the X value by itself, which means doing everything reverse. For example, you would subtract the 1 instead of adding it.

1 = 3x + 1

-1         -1

3x = 0

divide by 3 on both sides

x = 0

Let's check

3(0) + 1 = 6(0) + 1

1 = 1

This is a true statement

3 0
3 years ago
Read 2 more answers
Solve please ;3 ( will give brainliest ♡ )
VLD [36.1K]

Answer:

7

7 \times 4 + 3 \times  {4} ^{2}  \\ 28 + 58 \\ 86 \frac

8 0
3 years ago
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Omar has 2 3/4 cups of dough to make dumplings. if he uses 3/16 cup of dough for each dumpling , how many whole dumplings can Om
Damm [24]
Omar can make 14 whole dumplings. You change 2 3/4 cups to an improper fraction ( multiply the denominator and add the numerator ) and you get 11/4. Since you need 3/16 cups for one dumpling you have to find the greatest common denominator which is 16. You multiply 4 by 11 to get the numerator and end up with 44/16. Since you need 3/16 for one whole dumping you divide 44 by 3 and get 14.6 repeating. You cannot have a fraction of a dumpling so you round down and get the answer 14.
7 0
4 years ago
At the beginning of a lesson, a piece of chalk is 4.875 inches long. At the end of the lesson, it is 3.125 inches long. Write tw
natima [27]
Its probably 4 & 875/1000, 3 & 125/1000....hope this helps
7 0
4 years ago
The sum of two consecutive positive odd integers is two hundred sixty-four. find the two integers.
Daniel [21]

Any integer (not a fraction) that cannot be divided exactly by 2 is an odd integer.

So, we have ( 2k + 1 ) + ( 2k + 3 ) = 264, where 2k + 1 and 2k + 3 are the two consecutive positive odd integers ( k > 0 );

Then, 4k + 4 = 264;

4k = 260;

k = 65;

2k + 1 = 131;

2k + 3 = 133;

The chosen numbers are 131 and 133.

3 0
4 years ago
Read 2 more answers
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