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Citrus2011 [14]
3 years ago
13

Consider the following discrete time process: at integer times, a marble arrives which can be one of m colors. Each color is equ

ally likely; all events at different times are independent. As each marble arrives, it is placed into a bowl Unless there is a marble of that color already in the bowl. Then, that marble is removed from the bowl and the new marble does not go into the bowl. (The pair is placed in a separate bin for shipping). Let Gn denote the number of marbles currently in the bowl after the nth marble arrives. Compute,(a) the expectation E(Gn).(b) limn→[infinity] E(Gn).
Mathematics
1 answer:
Flauer [41]3 years ago
5 0

Answer:

Below are the responses to the given question:

Step-by-step explanation:

Let X become the random marble variable & g have been any function.

Now.

For point a:

When X is discreet, the g(X) expectation is defined as follows

Then there will be a change of position.

E[g(X)] = X x∈X g(x)f(x)

If f is X and X's mass likelihood function support X.

For point b:

When X is continuing the g(X) expectations is calculated as, E[g(X)] = Z ∞ −∞ g(x)f(x) dx, where f is the X transportation distances of probability.If E(X) = −∞ or E(X) = ∞ (i.e., E(|X|) = ∞), they say it has nothing to expect from EX is occasionally written to stress that a specific probability distribution X is expected.Its expectation is given in the form of,E[g(X)] = Z x −∞ g(x) dF(x). , sometimes for the continuous random vary (x). Here F(x) is X's distributed feature. The anticipation operator bears the lineage of comprehensive & integral features. The superposition principle shows in detail how expectation maintains equality and is a skill.

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Is the inequality always, sometimes, or never true?<br> 3x - 14 &lt; 3(x-5)
lys-0071 [83]

Answer:

3x - 14 < 3x - 15

-14 < -15

never true

Step-by-step explanation:

8 0
4 years ago
In the △ABC, the height AN = 24 in, BN = 18 in, AC = 40 in. Find AB and BC. Consider all possible cases. Case 1 : N∈BC, AB = __,
aivan3 [116]

Answer:

Case 1:

AB = 30

BC = 50

Case 2:

AB = 15.9

BC = 36.7

Case 3: Not possible

Step-by-step explanation:

Given

See attachment for illustration of each case

Required

Find AB and BC

Case 1:

Using Pythagoras theorem in ANB, we have:

AB^2 = AN^2 + BN^2

This gives:

AB^2 = 24^2 + 18^2

AB^2 = 576 + 324

AB^2 = 900

Take square roots of both sides

AB = \sqrt{900

AB = 30

To calculate BC, we consider ANC, where:

AC^2 = AN^2 + NC^2

40^2 = 24^2 + NC^2

1600 = 576 + NC^2

Collect like terms

NC^2 = 1600 - 576

NC^2 = 1024

Take square roots

NC = \sqrt{1024

NC = 32

So:

BC = NC + BN

BC = 32 + 18

BC = 50

Case 2:

Using Pythagoras theorem in ANB, we have:

AN^2 = AB^2 + BN^2

This gives:

24^2 = AB^2 + 18^2

576 = AB^2 + 324

Collect like terms

AB^2 = 576 - 324

AB^2 = 252

Take square roots of both sides

AB = \sqrt{252

AB = 15.9

To calculate BC, we consider ABC, where:

AC^2 = AB^2 + BC^2

40^2 = 252 + BC^2

1600 = 252 + BC^2

Collect like terms

BC^2 = 1600 - 252

BC^2 = 1348

Take square roots

BC = \sqrt{1348

BC = 36.7

Case 3:

This is not possible because in ANC

The hypotenuse AN (24) is less than AC (40)

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3 years ago
What is the measurement of the angle
Vadim26 [7]
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7 0
3 years ago
there are 148 juniors and 272 seniors attending prom this year. if there must be three chaperones per 60 students, how many chap
valkas [14]

21 chaperones are needed for 420 students.

Step-by-step explanation:

No. of juniors = 148

No. of seniors = 272

Total = 148+272 = 420 students

3 chaperones = 60 students

1 chaperone = \frac{60}{3}=20\ students

Ratio of chaperon to students = 1:20

Let,

x be the number of chaperons for 420 students.

Ration of chaperones to students = x:420

Using proportion

Ratio of chaperones to students :: Ratio of chaperons to students

1:20::x:420

Product of mean = Product of extreme

20*x=420*1\\20x=420\\

Dividing both sides by 20

\frac{20x}{20}=\frac{420}{20}\\x=21

21 chaperones are needed for 420 students.

Keywords: ratio, proportion

Learn more about ratios at:

  • brainly.com/question/4464845
  • brainly.com/question/4522984

#LearnwithBrainly

3 0
3 years ago
john bought 120 jars of honey to the farmers market. he sold 2/3 of the jars on sunday.how many jars are left to sell on sunday
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Answer:

The answer is 80. If you multiply 40 x 3 it is 120 and 40 x 2 is 80 so 2/3 of 120 is 80 NOT 40

5 0
3 years ago
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