Answer:
No
Step-by-step explanation:
Each x can have only ONE y as its partner. In this relation, -1 has TWO different partners: in one point (-1,-4) the y is -4 and in another point (-1,2) the y is 2. Not a function.
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term a and common ratio |r| < 1. Then the n-th partial sum (the sum of the first n terms) of the sequence is
Multiply both sides by r :
Subtract the latter sum from the first, which eliminates all but the first and last terms:
Solve for :
Then as gets arbitrarily large, the term will converge to 0, leaving us with
So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
23.
3•(-3)^2-4
3•(-3)^2
Exponents first.
-3^2=9
3•9=27
27-4= 2:.
-(9x+12)=-8x-(x+3)
-9x-12= -8x-x-3
-9x+9x=9
-9
if u look at the eq for x it has no value. but if u r asking a solution for a eq then it is -9
Answer:
The critical value for the 95% confidence interval is z = 1.96.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
So it is z with a pvalue of 
, so z = 1.96.
The critical value for the 95% confidence interval is z = 1.96.
