X = 77.789
y = 23...............................
Hey there,
Your question states: <span>The area on a wall covered by a rectangular poster is 294 square inches. The length of the poster is 1.5 times longer than the width of the poster. What are the dimensions of the poster? </span>
![l= 16 \ x \ 1.25 = 20 in](https://tex.z-dn.net/?f=l%3D%2016%20%5C%20x%20%20%5C%201.25%20%3D%2020%20%20in)
Your correct answer would be
![\boxed{20}](https://tex.z-dn.net/?f=%5Cboxed%7B20%7D)
Hope this helps.
They tell you that the length is 7 inches and that it is 2 inches more than the width therefore you can conclude that: length = 7 and the width = 5
you can plug the values given into the formula listed below:
A = lw
A = 7 x 5
A = 35
hope this helps :)
Answer:
![g(f(0))=-3](https://tex.z-dn.net/?f=g%28f%280%29%29%3D-3)
Step-by-step explanation:
we have
![f(x)=x^{2}](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D)
![g(x)=x-3](https://tex.z-dn.net/?f=g%28x%29%3Dx-3)
we know that
![(g o f)(x)=g(f(x))](https://tex.z-dn.net/?f=%28g%20o%20f%29%28x%29%3Dg%28f%28x%29%29)
substitute the variable x in the function g(x) by the function f(x)
so
![g(f(x))=x^{2}-3](https://tex.z-dn.net/?f=g%28f%28x%29%29%3Dx%5E%7B2%7D-3)
Evaluate ![g(f(0))](https://tex.z-dn.net/?f=g%28f%280%29%29)
For x=0
![g(f(0))=0^{2}-3](https://tex.z-dn.net/?f=g%28f%280%29%29%3D0%5E%7B2%7D-3)
![g(f(0))=-3](https://tex.z-dn.net/?f=g%28f%280%29%29%3D-3)