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3 years ago

Brenda has a square-shaped photo frame. If the area of the square frame is 123 square inches, which statement is true?

1 answer:

4 0

The length equals √123=11.09 inches
Therefore the statement "The length of the photo frame is between the 11 inches and 12 inches." is true.

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Students in elementary school attends school five days each week after three weeks of attendance each student has attended schoo

Naddika [18.5K]

Answer:

Step-by-step explanation:

first lets meake the minutes into hours by dividing our minutes into hours

6300 / 60 = 105

so in total they go 105 hours in 15 days (5 days for 3 weeks is 15 days)

to find how many hours in each day lets divide our hours into the 5 days

105 / 15 = 7 hours a day

hope this helps <3

8 0

3 years ago

What’s 1,234,948 rounded to the nearest 1,000,000

garik1379 [7]

Your answer would be 1,001,000

4 0

3 years ago

For f(x) = 4x+1 and g(x) =x^2-5 find (f times g) (4) apex

Dafna11 [192]

Answer:

$(f o g)(4) = 45$

Step-by-step explanation:

Step 1:-

Given f(x) = 4 x+1 and g(x) =x^2-5

$(f o g )(x) = f(g(x))$

Given

$(f 0 g)(4)=f(g(4))$

$f(g(4))=f(4^{2}-5)=f(11)$

$f(11)=4(11)+1 = 45$

Therefore $(f o g)(4) = 45$

6 0

3 years ago

A bacterial culture starts with 500 bacteria and doubles in size every half-hour.

tekilochka [14]

Answer:

a). 32000

b). $T_{t}=500\times 4^{t}$

c). 1259

Step-by-step explanation:

Growth of a bacteria is always exponential. Therefore, population of the bacteria is represented by the the geometric sequence.

Sum of the bacterial population after t hours will be represented by

$T_{n}=ar^{n}$

Where a = population at the start

r = ratio with the population is growing

n = time or duration of the growth in one hour

a). Population of 500 bacteria gets doubled after half an hour.

Or gets 4 times after an hour

This sequence will have a common ratio r = 4

and initial population a = 500

Therefore, population of the bacteria after 3 hours will be

$T_{3}=500\times 4^{3}$

$T_{3}=32000$

b). After t hours number of bacteria will be represented by

$T_{t}=500\times 4^{t}$

c). We have to calculate the population after 40 minutes.

That means duration 't' = 40 minutes of $\frac{2}{3}$ hours

By the formula,

$T_{\frac{2}{3}}=500\times 4^{\frac{2}{3}}$

$T_{\frac{2}{3}}=1259.92$ ≈ 1259

Therefore, number of bacteria after 40 minutes will be 1259.

8 0

3 years ago

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What are the roots of the equation? x^2(6x−11)(7x−8)=0

trasher [3.6K]

multiply all the factors in x^2

to get the roots which are 0, 11/6 and 8/7

3 0

3 years ago

Read 2 more answers