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3 years ago

Please help me with these two problems. Thank you so much

Mathematics

1 answer:

SVEN [57.7K]3 years ago

8 0

A title could be the effect of the amount/number of days on the amount/number of bacteria. For the 2nd The IV is temperature, the DV is Enzyme Activity and a title could be The effect of Temperature on Enzyme activity.

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What is the graph of the exponential function y=1.5 to the x power?

xxMikexx [17]

These are what you can plot:
(-2, 0.444), (-1, 0.667), (0,1), (1, 1.5,), (2,2.25)

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3 years ago

Read 2 more answers

2. You want to spin yellow. Which spinner should you spin? Explain,

Furkat [3]

Answer:

sppiner A

Step-by-step explanation:

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3 years ago

Last year, Edward spent a total of $626.14 on his power bill. Rounding the total bill to the nearest tens place, approximate how

zlopas [31]

Answer:

He spent around $ 52.17 in each month.

Step-by-step explanation:

Last year the power bill price = $ 626.14 ≈ $ 626

We know that in a year 12 months. so power bill of each month in last year is calculated as follows

$Power \ bill \ of \ each \ month = \frac{Total \ bill \ of \ the \ year}{12}$

$Power \ bill \ of \ each \ month = \frac{626}{12}$

$Power \ bill \ of \ each \ month =$ $ 52.17

Therefore he spent around $ 52.17 in each month.

7 0

4 years ago

A boat is travelling from point C toward point D which is on the shoreline. The shoreline is represented by the line through poi

amid [387]

I believe it B but I’m not quiet sure

7 0

3 years ago

Suppose that 10% of the undergraduates at a certain university are foreign students, and that 25% of the graduate students are f

Deffense [45]

Answer:

0.6154 = 61.54% probability that the student is an undergraduate

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Foreign

Event B: Undergraduate.

There are four times as many undergraduates as graduate students

So 4/5 = 80% are undergraduate students and 1/5 = 20% are graduate students.

Probability the student is foreign:

10% of 80%

25% of 20%. So

$P(A) = 0.1*0.8 + 0.25*0.2 = 0.13$

Probability that a student is foreign and undergraduate:

10% of 80%. So

$P(A \cap B) = 0.1*0.8 = 0.08$

What is the probability that the student is an undergraduate?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.08}{0.13} = 0.6154$

0.6154 = 61.54% probability that the student is an undergraduate

8 0

3 years ago