$\dfrac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}=\dfrac{\frac{y}{xy}-\frac{x}{xy}}{\frac{y}{xy}+\frac{x}{xy}}=\dfrac{\frac{y-x}{xy}}{\frac{y+x}{xy}}=\dfrac{(y-x)xy}{(y+x)xy}=\dfrac{y-x}{y+x}$

Answer D.

6 0

3 years ago

What is the answer to 2x+4y=16:4y=12

allsm [11]

Answer:

Here,

$2x + 4y = 16....eqn \: i \\ 4y = 12....eqn \: ii$

substituting the value of 4y in eqn i fron eqn ii

so eqn i becomes

$2x + 12 = 16 \\ 2x = 4 \\ x = 2$

$y = 12 \div 4 = 3$

Thus,

$x = 2 \: and \: y = 3$

...hope this helps:)

8 0

2 years ago

Mr. green has a garden. Of the 40 seeds he planted, 35% were vegetable seeds. How many vegetable seeds did he plant

Lelechka [254]

Answer:

Step-by-step explanation:

35% of 40 is 14

8 0

2 years ago

Read 2 more answers

Find two numbers witha sum of 20 and a difference of 14

bixtya [17]

from the given equation

X+Y=20-->i

X-Y=14--->ii

add eq i and eq ii

2x=34

x=17

putting the value of x=17 in eq i

17+y=20

then y = 3 so the right answer is

17 and 3

6 0

4 years ago