All categories

3 years ago

Evaluate -4n^2+ 11 when n= 3

Mathematics

2 answers:

jok3333 [9.3K]3 years ago

8 0

Answer:

Step-by-step explanation:

999

lisabon 2012 [21]3 years ago

6 0

Since you know the value of n, you can substitute/plug it into the equation:

-4n² + 11 Plug in 3 into "n" since n = 3

-4(3)² + 11 Find 3² --> 3 x 3 = 9

-4(9) + 11 Multiply -4 and 9

-36 + 11

-25

You might be interested in

What is the area of the piece of red paper after the hole for

MakcuM [25]

Answer:

$\large\boxed{\large\boxed{47unit^2}}$

Explanation:

The complete question is:

A hole the size of a photograph is cut from a red piece of paper to use in a picture frame.

On a coordinate plane, 2 squares are shown. The photograph has points (-3, -2), (- 2, 2), (2, 1), and (1, -3). The red paper has points (- 4, 4), (4, 4), (4, -4), and (-4, -4).

What is the area of the piece of red paper after the hole for the photograph has been cut?

<h2>Solution</h2>

The area of the piece of redpaper after the hole has been cut is equal to the area of the big square less the area of the small rectangle.

1. Area of the big rectangle

Vertices:

(- 4, 4)
(4, 4)
(4, -4)
(-4, -4)

The side length is the distance between two consecutive vertices:

The two points (-4,4) and (4,4) has the same y-coordinate, thus the length is just the absolute value of the difference of the x-coordinates:

$4-(-4)=4+4=8$

The area of this square is $(8unit)^2=64unit^2$

2. Area of the small square

Vertices:

(-3, -2)
(- 2, 2)
(2, 1)
(1, -3)

To find the side length use the distance formula for two consecutive points, for instance (2,1) and (-2,2):

$d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\ \\d=\sqrt{(2-(-2))^2+(2-1)^2}=\sqrt{4^2+1^2}=\sqrt{17}$

The area is:

$(\sqrt{17}unit)^2}=17unit^2$

3. Area of the piece of red paper after the holw for the photograph has been cut:

Find the difference:

$64unit^2-17unit^2=47unit^2$

7 0

3 years ago

Read 2 more answers

What is (6.2*10^4)*(3.3*10^2) in scientific notation

Free_Kalibri [48]

Its 2.046*10^7 hope this helps you :)

8 0

3 years ago

I dont know how she got her anser pleas help

valkas [14]

The formula for volume is length times width times height
The length is 5
The width is 2.4
The height is 8
2.4 times 8 times 5=96 cubic feet

7 0

3 years ago

Christine has always been weak in mathematics. Based on her performance prior to the final exam in Calculus, there is a 51% chan

Charra [1.4K]

Answer:

a) 0.3270 = 32.70% probability that Christine fails the course

b) 0.3917 = 39.17% probability that she had found someone to help

Step-by-step explanation:

We have these following probabilities:

61% probability that Christine find a coach.

100 - 61 = 39% probability that Christine does not find a coach.

With a coach, a 21% probability of failing.

Without a coach, a 51% probability of failing.

a. What is the probability that Christine fails the course?

21% of 61%(finds a tutor) plus 51% of 39%(does not find a tutor). So

P = 0.21*0.61 + 0.51*0.39 = 0.327.

0.327 = 32.7% probability that Christine fails the course

b. Christine ends up failing the course. What is the probability that she had found someone to help?

This can be formulated by the Bayes formula:

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening given that A happened and P(A|B) is the probability of A happening given that B happened.

In this question.

P(B|A) is the probability of finding a tutor given that she failed.

P(B) is the probability of finding a tutor. So P(B) = 0.61.

P(A|B) is the probability of failing when finding a tutor. So P(A|B) = 0.21

P(A) is the probability of failing. So P(A) = 0.327.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)} = \frac{0.61*0.21}{0.327} = 0.3917$

0.3917 = 39.17% probability that she had found someone to help

4 0

3 years ago

15 divided by 6 2/3=

SCORPION-xisa [38]

15 divided by 6 2/3 is 2 1/4

3 0

3 years ago

Read 2 more answers