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Dmitry_Shevchenko [17]
3 years ago
10

6) Matthew went to SAMS and bought 6 packs of 12 honey buns he is going to sell at his

Mathematics
1 answer:
NARA [144]3 years ago
5 0

Answer:

2313

Step-by-step explanation:

123123

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S=πrl+πr2 solve for l.
kipiarov [429]

Answer:

<h2>l =  \frac{s - π {r}^{2} }{πr}</h2>

Step-by-step explanation:

s = πrl + πr²

First move πr² to the left side of the equation

We have

πrl = s - πr²

Divide both sides by πr to make l stand alone

That's

<h3>\frac{\pi \:rl}{\pi \: r}  =  \frac{s - \pi \:  {r}^{2} }{\pi \: r}</h3>

We have the final answer as

<h3>l =  \frac{s - π {r}^{2} }{πr}</h3>

Hope this helps you

5 0
3 years ago
Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e^−2
Mekhanik [1.2K]

Answer:

x=1

y=s

z=1

Step-by-step explanation:

(x, y, z)=(1, 0, 1)

Substitute 0 for y

y = e^{-2t} *sin 4t\\0 = e^{-2t} *sin 4t\\\\0 = e^{-2t} *(\frac{e^{4t}-e^{-4t}}{2j} )\\0 = e^{-2t} *(e^{4t}-e^{-4t} )\\0 = e^{-2t} *e^{4t}*(1-e^{-8t} )\\\\0 = e^{2t}*(1-e^{-8t} )\\\\\\Either   \\0 = e^{2t}\\t = -inf\\or\\0 = (1-e^{-8t} )\\(e^{-8t} ) = 1\\ -8t = ln(1) =0\\t=0\\\\

Confirming if t=0 satisfy the other equation

x = e^−2t cos 4t = e^−2(0)cos(4*0)

= e^(0)cos(0) = 1

z = e^−2t  = e^−2(0)  = 0

Therefore t=0 satisfies the other equation

Finding the tangent vector at t=0

\frac{dx}{dt}=-2te^{-2t} cos4t + e^{-2t}(-4sin4t)=-2(0)e^{-2(0)} cos4(0) + e^{-2(0)}(-4sin4(0))=0\\\\ \frac{dy}{dt} =-2te^{-2t} sin4t + e^{-2t}(4cos4t)=-2(0)e^{-2(0)} sin4(0)+ e^{-2(0)(4cos4(0)) }= 1\\\\\frac{dz}{dt}  = -2te^{-2t}  = -2(0)e^{-2(0)}  = 0

The vector equation of the tangent line is

(1, 0, 1) +s(0,1,0)= (1, s, 1)

The parametric equations are:

x=1

y=s

z=1

6 0
3 years ago
Find the Quotient.<br>4,298 ÷ 4​
posledela

Answer:

1074.5 or 1074 1/2

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Miguel and Jacqui built towers out of craft sticks. Miguel’s tower had a 4-inch square base. Jacqui’s tower had a 6-inch square
Lapatulllka [165]
Jacquis is i think i don’t know
7 0
3 years ago
Read 2 more answers
4. (03.03 HC)
Kitty [74]

Answer:

A. yes, the data represents a function because u have no repeating x values. A function cannot have repeating x values...they can have repeating y values, just not the x ones

Step-by-step explanation:

B. table : (8,8)(12,12)(14,16)(16,16)

               look at ur points...when x = 8, y = 8...so the table, when x = 8 has a

               value of 8

relation : f(x) = 8x - 5....when x = 8

             f(8) = 8(8) - 5

             f(8) = 64 - 5

             f(8) = 59....and the relation has a value of 59

Therefore, the relation has a greater value when x = 8 <==

C. f(x) = 8x - 5...when f(x) = 19

    19 = 8x - 5

     19 + 5 = 8x

    24 = 8x

    24/8 = x

    3 = x <==

7 0
3 years ago
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