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kodGreya [7K]
3 years ago
13

12. Based on a population mean (u) of 20 and a population standard deviation (6) of 5, what is the probability of a getting a sc

ore between 10 and 15? (15 points) Hint: Draw a normal curve and shade the area you're interested in finding the probability for to determine which shaded sides of the unit normal table you need to pull numbers from. ​
Mathematics
1 answer:
pashok25 [27]3 years ago
7 0
I will need a little more information
You might be interested in
Someone that understand this can help me out?
Kryger [21]
Plug in -2 to x in the formula
So f(-2)= ((-2)+1)^2
Your answer should be: 1
7 0
3 years ago
What is the equation of the line that is parallel to the given line and passes through the point (2, 3)?
Lelechka [254]

Answer:

(-4,0)(4,-4)

slope(m) = (-4 - 0) / (4 - (-4) = -4/(4 + 4) = -4/8 = -1/2. A parallel line will have the same slope.

y = mx + b

slope(m) = -1/2

(2,3)...x = 2 and y = 3

now we sub and find b, the y int

3 = -1/2(2) + b

3 = -1 + b

3 + 1 = b

4 = b

y = -1/2x + 4

1/2x + y = 4....multiply by 2

x + 2y = 8 <== ur parallel line

3 0
3 years ago
Read 2 more answers
Please answer this! &amp; explain how to get the answers.
konstantin123 [22]

 (x - 2) • (x - 3) • (x - 4) • (x - 5)

Step by step solution :

Step  1  :

Equation at the end of step  1  :

 ((((x4)-(14•(x3)))+71x2)-154x)+120

Step  2  :

Equation at the end of step  2  :

 ((((x4) -  (2•7x3)) +  71x2) -  154x) +  120

The factor(s) are:

of the Leading Coefficient :  1

of the Trailing Constant :  1 ,2 ,3 ,4 ,5 ,6 ,8 ,10 ,12 ,15 , etc

6 0
3 years ago
A population of squirrels on an island has a carrying capacity of 350 individuals. If the maximum rate of increase is 1.0 per in
TiliK225 [7]

Answer:

The population growth rate is <u>59</u> squirrels per year.

Step-by-step explanation:

Given:

A population of squirrels on an island has a carrying capacity of 350 individuals. If the maximum rate of increase is 1.0 per individual per year and the population size is 275.

Now, to find the population growth rate.

Carrying capacity (K) = 350.

Maximum rate (r_{max}) = 1.0 per individual per year.

Population size (N) = 275.

Now, to get the population growth rate we put formula:

\frac{dN}{dT}= r_{max}\frac{K-N}{K}N

\frac{dN}{dT}=1.0\times \frac{350-275}{350}\times 275\\\\\frac{dN}{dT}=1.0\times \frac{75}{350}\times 275\\\\\frac{dN}{dT}=1.0\times 0.214\times 275\\\\\frac{dN}{dT}=58.85.

<u><em>So, rounding to nearest whole number of the population growth rate is 59 squirrels per year.</em></u>

Therefore, the population growth rate is 59 squirrels per year.

6 0
3 years ago
When Maria finished medical school, she owed $36,000 in student loans. She repaid of the total
Viktor [21]

Answer:

$24,000

Step-by-step explanation:

To find how much she owed, find 2/3 of 36,000, since she repaid 1/3

36000(2/3)

= 24,000

So, two years after graduating, Maria owed $24,000

7 0
3 years ago
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