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Oliga [24]
4 years ago
14

How many degrees are in the following sum?

Mathematics
1 answer:
Amiraneli [1.4K]4 years ago
4 0
I THINK ITS C.135 DEGREES

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Determine if the sequence below is arithmetic or geometric and determine the
algol13

9514 1404 393

Answer:

  r = 2

Step-by-step explanation:

The first differences between successive terms are ...

  10 -5 = 5

  20 -10 = 10

The differences are not constant, so the sequence is NOT arithmetic.

__

The ratios of successive terms are ...

  10/5 = 2

  20/10 = 2

The ratios are constant, so the sequence is ...

  geometric with a common ratio of 2.

4 0
3 years ago
Anyone mind helping me solve this inequality? Step by step
dlinn [17]

By decomposing the figure in simpler shapes, we will see that the total area is:

a = 180 cm²

<h3>How to find the area of the composite figure?</h3>

Remember that the area of a rectangle of width W and length L is:

A = L*W

And the area of a triangle with base B and height H is:

A = B*H/2.

Then, the upper part can be seen as a rectangle of length of 6cm and width of 6 cm, with two triangles on the sides, such that each triangle has a base of 3cm and a height of 6cm.

So the area of that part is:

A = 6cm*6cm + 2*(3cm*6cm/2) = 54cm²

Now, the bottom triangle has a base of 12 cm, and a height of:

15cm - 6cm = 9cm

Then its area is:

A' = 12cm*9cm/2 = 54cm²

This means that the total area of the figure is:

total area = 54cm² + 54cm² = 108cm²

If you want to learn more about area:

brainly.com/question/24487155

#SPJ1

5 0
2 years ago
Someone please help math question?ASAP
natali 33 [55]
A I am pretty sure. I apologize if I am incorrect. 
3 0
3 years ago
What is the value of x?
ioda

Answer:

50.714 (3 dp)

Step-by-step explanation:

Using trigonometry.

cos(\theta)=\frac{adj}{hyp} \\adj = hyp  * cos(\theta)\\120*cos(65) = 50.714

7 0
3 years ago
James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

The needed function is y = 2 ^n

Step-by-step explanation:

Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

n : the number of times the paper is folded.

y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
4 years ago
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