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yawa3891 [41]
3 years ago
11

Harry and Ron are standing next to each other. Harry walks 15 feet north towards Hogwarts

Mathematics
1 answer:
AleksAgata [21]3 years ago
8 0
Just subtract 15-12=13
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Please answer something relevant to this question ,I really need help with this
belka [17]
First you need to substitute the xs and ys into point slope ( y1 - y2 = m(x1 - x2). in this example it would be 3-6= m(0 - (-1)). then you just simplify, so -3 = m(1) -3=m. the slop is -3. because you already know the y-intercept is 3 (0,3), you can substitute everything into slope intercept (y=mx+b). so the answer is y=-3x+3.

I hope this helped, let me know if you are still confused and i can help :)
5 0
3 years ago
What is the total price of a $45 pair of jeans after a 6.5% sales tax is added?<br> show ur work
tangare [24]
The answer is 45.65
45 + 6.5 = 45.065

45 divided by 6.5 over a hundred = 45 + 0.065


Thats how you get 45.65
6 0
3 years ago
Read 2 more answers
Prove that (Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A
iVinArrow [24]

Answer:

The answer is below

Step-by-step explanation:

We need to prove that:

(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.

Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.

Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A

\frac{\sqrt{secA-1} }{\sqrt{secA+1} } +\frac{\sqrt{secA+1} }{\sqrt{secA-1} } =\frac{(\sqrt{secA-1)}(\sqrt{secA-1})+(\sqrt{secA+1)}(\sqrt{secA+1}) }{(\sqrt{secA+1})(\sqrt{secA-1}) } \\\\=\frac{secA-1+(secA+1)}{\sqrt{sec^2A-secA+secA-1} } \\\\=\frac{2secA}{\sqrt{sec^2A-1} } \\\\=\frac{2secA}{\sqrt{tan^2A} } \\\\=\frac{2secA}{tanA} \\\\=\frac{2*\frac{1}{cosA} }{\frac{sinA}{cosA} }\\\\= 2*\frac{1}{cosA}*\frac{cosA}{sinA}\\\\=2*\frac{1}{sinAA}\\\\=2cosecA

7 0
2 years ago
Is this the relation R:={(2,1),(3,1),(5,5),(7,5)} a function?
fredd [130]
<h3>Answer: Yes, it is a function</h3>

This is a function because there are no x values that repeat.

If we had repeated x values, then this would mean a certain input x leads to multiple outputs y, and that would not make it a function.

For instance, if we had (2,1) and (2,2) at the same time, then the input x = 2 leads to multiple outputs y = 1 and y = 2 at the same time. A function would not be possible in this example.

A function is only possible if any input x leads to exactly one output y. It is possible for y to repeat itself and still have a function.

7 0
2 years ago
Help please I will give points​
Romashka [77]
Last one full points try to add and help me out plz
4 0
3 years ago
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