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3 years ago

Volume of a circular cylinder 4 feet tall with a radius of 15Ft.

Mathematics

2 answers:

Yuri [45]3 years ago

4 0

Answer:

2827.43

Step-by-step explanation:

tekilochka [14]3 years ago

3 0

Answer:

Volume = 60 ft

Step-by-step explanation:

You would just simply multiply the two numbers together ( 4 x 15= 60)

So V=60ft

~ Hope this has helped ya in any way, have a gr8 day/night my friend!~

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Ir[ Fairbanks, the temperature at 6:00 AM on Sunday is - 48°F. The weather forecast

mestny [16]

Answer:

The answer is 3 days

Step-by-step explanation:

Divide 48/16=3

6 0

3 years ago

Which of the following can be used to represent a loss of $320. -320, 0, 1 over 320, +320

Radda [10]

-320. The negative sign represents loss. In all of the other cases, values are either being added or not changed at all.

4 0

3 years ago

Students sold raffle tickets to raise money for a field trip. The first 20 tickets cost $4 each. To sell more tickets, they lowe

saveliy_v [14]

Answer:

88 Tickets were sold

Step-by-step explanation:

20*$4=$80

$216-$80=$136

$136/2=68

20+68=88 tickets

4 0

3 years ago

Find the measure of each acute angle. Thank you!

Wewaii [24]

Answer:

55 for the top left and 35 for the top right

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

7x+6 + 6x -7 + 90 = 180

Combine like terms

13x+89 = 90

Subtract 89 from each side

13x+89-89 = 180-89

13x = 91

Divide by 13

13x/13 = 91/13

x =7

The top left angle is

7x+6

7*7+6 = 49+6 = 55

The top right angle is

6x-7

6*7-7 = 42-7 = 35

3 0

3 years ago

Use the method of reduction of order to find a second independent solution of the given differential equation. t2y'' + 3ty' + y

Charra [1.4K]

I assume you mean $y_1=t^{-1}$ , and not $y_1=t-1$ , since this doesn't satisfy the ODE.

Assume a second solution of the form $y_2=vy_1$ , where $v$ is a function of $t$ . Then

${y_2}'=v'y_1+v{y_1}'$

${y_2}''=v''y_1+2v'{y_1}'+v{y_1}''$

Substituting into the ODE gives

$t^2\left(\dfrac{v''}t-\dfrac{2v'}{t^2}+\dfrac{2v}{t^3}\right)+3t\left(\dfrac{v'}t-\dfrac v{t^2}\right)+\dfrac vt=0$

$\implies tv''+v'=0$

$\implies(tv')'=0$

$\implies tv'=C$

$\implies v'=\dfrac Ct$

$\implies v=C_1\ln|t|+C_2$

$\implies y_2=\dfrac{\ln t}t$

where we omit the second term because it's already accounted for by $y_1$ .

3 0

3 years ago