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3 years ago

HLP HLP 10 10 10 HLP HLP HLP W

Mathematics

2 answers:

lesantik [10]3 years ago

7 0

Answer:

A. 6²¹

Step-by-step explanation:

When you have a number raised to the power in that form, you have to multiply the powers:

(6⁷)³

7×3 = 21

(6⁷)³ = 6²¹

grigory [225]3 years ago

6 0

Answer:

A. 6 raise to 21

Step-by-step explanation:

its a formula if:

a raise to m whole raise to n = a raise to m×n

so here

6 raise to 7 × 3

that is 6 to the power of 21

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If f(x)= 3x2 and g(x) = x+2, find (f.g)(x).

Paha777 [63]

Step-by-step explanation:

$f(x) = 3 {x}^{2} \: and \: g(x) = x + 2 \\ (f.g)(x) \\ = f(x).g(x) \\ = 3 {x}^{2} .(x + 2) \\ \red{ \boxed{ \bold{ \therefore f(x).g(x)= 3 {x}^{3} + 6 {x}^{2} }}} \\$

7 0

3 years ago

I di not understand these any help greatly appreciated thank you

Rzqust [24]

Answer:

Step-by-step explanation:

First you need to convert it to a linear expression.

3x - y = 4

+3x +3x

-1y = 3x + 4

--- ----- -----

-1 -1 -1

y = -3x -4

6x - 2y = 7

-6x -6x

-2y = -6x + 7

---- ----- -----

-2 -2 -2

y = 3x - 3.5

-3x - 4 = 3x - 3.5

+3x +3x

-4 = 6x - 3.5

+3.5 +3.5

-0.5 = 6x

----- -----

6 6

-0.5

------ = x

4 0

3 years ago

4-(2x-3) = 3(x + 1) <br> i need steps too

ozzi

Next time u can use math papa. it's a app that will help u too

8 0

3 years ago

Read 2 more answers

Solve the system y=x²-2 and x²+y=4.Illustrate graphically.

lawyer [7]

Answer:

Solution: $(-\sqrt{3},1),(\sqrt{3},1)$

Step-by-step explanation:

System of equation:

$y=x^2-2\text{ and }x^2+y=4$

Using substitution method.

$y=x^2-2$ substitute into $x^2+y=4$

$x^2+x^2-2=4$ (combine like term)

$2x^2=4+2$ (Addition property of equality)

$2x^2=6$ (division property of equality)

$x^2=3$ (Taking square root)

$x=\pm \sqrt{3}$

Substitute x into $y=x^2-2$

$y=(\sqrt{3})^2-2$

$y=1$

Solution: $(-\sqrt{3},1),(\sqrt{3},1)$

Now cross check the solution using graph.

Please find attachment for graph.

4 0

3 years ago

Does anyone know what these 2 problems are? The answer is on the bottom. :)

In-s [12.5K]

Hi, hope you’re having a good day!

Do you have the full picture? Please send if so.

Thanks! Have a great day! ❤️❤️

3 0

3 years ago