Answer:
x = 41.2 m
Explanation:
The electric force is a vector magnitude, so it must be added as vectors, remember that the force for charges of the same sign is repulsive and for charges of different sign it is negative.
In this case the fixed charges (q₁ and q₂) are positive and separated by a distance (d = 100m), the charge (q₃ = -1.0 10⁻³ C)) is negative so the forces are attractive, such as loads q₃ must be placed between the other two forces subtract
F = F₁₃ - F₂₃
let's write the expression for each force, let's set a reference frame on the charge q1
F₁₃ =
F₂₃ =
they ask us that the net force be zero
F = 0
0 = F₁₃ - F₂₃
F₁₃ = F₂₃
k \frac{q_1 q_3}{x^2} =k \frac{q_2 q_3}{(d-x)^2}
q1 / x2 = q2 / (d-x) 2
(d-x)² = x²
we substitute
(100 - x)² = 2/1 x²
100- x = √2 x
100 = 2.41 x
x = 41.2 m
<span>The potential energy is mgh. The kinetic energy is (1/2)mv^2. Total mechanical energy means the sum of those. The velocity is 0 since its just hanging.
A 0.100-kilogram apple falls from a height of 1.50 meters to 1.00 meters. Ignoring frictional effects, what is the kinetic energy of the apple at this height? Its equal to the change in PE from 1.5 meters to 1.0 meters. PE = mgh.</span>
Chlorophyll traps the light energy given off by the Sun and converts it to chemical energy required to drive photosynthesis
Answer: s(5) = -200, v(5) = -90
s(10) = -900, v(10) = -190
<u>Explanation:</u>
Position: s(t)
Velocity: s'(t) = v(t) ⇒
Acceleration v'(t) = a(t) ⇒
We are given that acceleration a(t) = -20 and velocity v(t) = 10
(a) Input t = 5 into the s(t) and v(t) equations
s(5) = -10(5)² + 10(5) v(5) = -20(5) + 10
= -250 + 50 = -100 + 10
= -200 = -90
(b) Input t = 10 into the s(t) and v(t) equations
s(10) = -10(10)² + 10(10) v(10) = -20(10) + 10
= -1000 + 100 = -200 + 10
= -900 = -190