Answer:
Explanation:
Given that
Mass of bowling ball M1=7.2kg
The radius of bowling ball r1=0.11m
Mass of billiard ball M2=0.38kg
The radius of the Billiard ball r2=0.028m
Gravitational constant
G=6.67×10^-11Nm²/kg²
The magnitude of their distance apart is given as
r=r1+r2
r=0.028+0.11
r=0.138m
Then, gravitational force is given as
F=GM1M2/r²
F=6.67×10^-11×7.2×0.38/0.138²
F=9.58×10^-9N
The force of attraction between the two balls is
F=9.58×10^-9N
<span>heat transfer though convection</span>
Answer:
The horizontal distance from the to the bottom of the pool is 3.831 m
Solution:
As per the question;
Height of the pool, H = 1.5 m
Depth of the pool, D = 2.75 m
Refractive index of air,
Refractive index of air,
Angle of the beam at the water surface,
Now,
The angle of incidence is given by
Now, using Snell's law:
Now,
From the normal, the horizontal image distance, d' is given by:
Now,
From the normal, the horizontal object distance, d'' is given by:
Thus the horizontal distance is given by:
d' + d'' = 1.979 + 1.852 =3.831 m
13: 2 hydrogen 1 sulfur 4 oxygen