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katen-ka-za [31]
3 years ago
7

A police car is traveling at a speed of 50 meters per second when it suddenly accelerates at a rate of 5 m/s2. How fast will the

car be going (final velocity) if it maintains that acceleration for 30 seconds
Physics
1 answer:
Virty [35]3 years ago
6 0

Answer:i don't know sorry good luck tho

Explanation: i have not learned it yet

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In an experiment performed in a space station, a force of 60 N causes an object to have an acceleration equal to 4m/s. What is t
Naddik [55]

I'm afraid you're not paying attention.  This question is loaded with
all the important words, and you don't recognize Newton's second
law of motion.  Didn't you notice the  "force", "acceleration", and
"mass" all over the place in there ?

Newton's 2nd law:      Force = (mass) x (acceleration)

The answer is going to be 'mass', so let's divide
each side of Newton's law by 'acceleration':

                                   Mass = (force) / (acceleration)

Now, just write in the numbers that the question gave you:

                  force =  60 newtons
       acceleration =  4 m/s²

Here's the equation again:     Mass = (force) / (acceleration)      

                                                       = (60 N) / (4 m/s²)

                                                       =  15 kg .  

3 0
4 years ago
When humans started launching rockets into outer space, they needed to make certain the rockets had enough power to escape Earth
GaryK [48]
Tha answer has to be a
5 0
3 years ago
WILL GLADLY GIVE BRAINIEST FOR THIS EASY QUESTION
Alekssandra [29.7K]

The atomic number of Copper is 29.  So immediately we know that there are <em>29 protons </em>in the nucleus of each Copper atom, and <em>29 electrons</em> in the cloud surrounding the nucleus of each [neutral] Copper atom.

Copper has two stable isotopes ... ⁶³Copper and ⁶⁵Copper.  So if the Copper atom you're holding in your hand is not radioactive, then it has either (63-29)=<em>34 neutrons</em> or (65-29)=<em>36 neutrons</em> in its nucleus. (There's never a need to round the number of neutrons, because there's no such thing as a <em>part </em>of a neutron.)

4 0
3 years ago
Read 2 more answers
A motorcycle is following a car that is traveling at constant speed on a straight highway. Initially, the car and the motorcycle
aalyn [17]

Answer:

4.56 s

Explanation:

Let t (seconds) be the time it takes from the moment when the motorcycle starts to accelerate until it catches up with the car. Since prior to this they are traveling at constant speed, they would have maintained a distance of 52 m before accelerating.

The distance traveled by the car, with respect the motorcycle position when it start accelerating is

s_c = s_0 + v_ct = 52 + 19t

The distance traveled by the motorcycle after accelerating, with respect the motorcycle position when it start accelerating is

s_m = v_mt + at^2/2 = 19t + 5t^2/2

When the motorcycle catches up to the car, their position are at the same

s_c = s_m

52 + 19t = 19t + 5t^2/2

52 = 5t^2/2

t^2 = 20.8

t = \sqrt{20.8} = 4.56 s

5 0
3 years ago
A banked circular highway curve is designed for traffic moving at 58 km/h. The radius of the curve is 201 m. Traffic is moving a
skelet666 [1.2K]

Answer:0.077

Explanation:

Given

banked designed for traffic moving at 58 km/h\approx 16.11 m/s

Radius of the curve 201 m

Actual traffic velocity =37 km/h approx  10.27 m/s

For banking of road

tan\theta =\frac{v^2}{rg}

tan\theta =\frac{16.11^2}{201\times 9.81}

\theta =7.49^{\circ}

Centripetal acceleration is given by

a=\frac{v^2}{r}

Taking component of centripetal acceleration

along and perpendicular to surface

a_{parallel}=\frac{v^2cos\theta }{r}

a_{perpendicular}=\frac{v^2sin\theta }{r}

From FBD

mgsin\theta -f_s=ma_{parallel}

f_s=mgsin\theta -ma_{parallel}----1

where f_s is frictional force

N-mgcos\theta =ma_{perpedicular}

N=mgcos\theta +ma_{perpedicular}----2

and we know coefficient of friction is given by

\mu =\frac{f_s}{N}

\mu =\frac{mgsin\theta -ma_{parallel}}{mgcos\theta +ma_{perpedicular}}

\mu =\frac{gsin\theta -\frac{v^2cos\theta }{r}}{gcos\theta +\frac{v^2sin\theta }{r}}

\mu =\frac{1.2804-0.5202}{9.726+0.068}

\mu =0.077

7 0
3 years ago
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