The quantity of heat must be removed is 1600 cal or 1,6 kcal.
<h3>Explanation : </h3>
From the question we will know if the condition of ice is at the latent point. So, the heat level not affect the temperature, but it can change the object existence. So, for the formula we can use.

If :
- Q = heat of latent (cal or J )
- m = mass of the thing (g or kg)
- L = latent coefficient (cal/g or J/kg)
<h3>Steps : </h3>
If :
- m = mass of water = 20 g => its easier if we use kal/g°C
- L = latent coefficient = 80 cal/g
Q = ... ?
Answer :

So, the quantity of heat must be removed is 1600 cal or 1,6 kcal.
<u>Subject : Physics </u>
<u>Subject : Physics Keyword : Heat of latent</u>
In that case, heat energy flows from the warmer object to the cooler one.
As heat flows from one to the other, the temperature of the warmer object
falls, and the temperature of the cooler object rises. When the temperatures
are equal, the flow of heat energy from one to the other stops.
Answer:
450000 kg m/s
Explanation:
convert 108km/h to m/s
1km=100m
1h=(60×60)s = 3600s
108km/h= (108×1000)÷3600
=30m/s
K.E =1/2mv^2
=1/2(1×10^3)(30^2)
= 1/2 × 1000 × 900
= 450000 kg m/s
this should be your answer, hope I was able to help.
The equation we need to use is Ohm's Law
Voltage = Current * Resistance
Voltage = 6A * 3<span>Ω = 18 Volts</span>