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2 years ago

Help please i really want to pass this quiz

Physics

1 answer:

Lesechka [4]2 years ago

5 0

Answer:

It is positive and smaller in magnitude than the initial acceleration.

Explanation:

We know that acceleration is defined as the change of velocity in a given time.

We see that the time interval is equal to 30 seconds (70 - 40). In this interval we also see that the velocity increases from 245 to 250 (m/s) approximately. Therefore the acceleration is positive.

With respect to the magnitude we can say that it is smaller than at the beginning since the change of velocities is smaller with respect to the change of velocities at the beginning.

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Why smartphone and computer are called modern technology?

topjm [15]

Answer:

Hey

I am sure from what i know that your answer should be the following:

Modern technology is deeply tied to efficiancy and speed. Think of the knew 5G network it gives us very fast internet, or perhaps our very nessisitys such as our phone or cumputer. On a phone you have so much (thats to say you can acces alot easly); pictures videos dictionarys video games etc etc.

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If you drop a bowling ball, a tennis ball, and a feather from the top of a tall building at the same time which one will hit the

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In the absence of air resistance the result is D .

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Will an object with more mass roll faster down a hill?

inna [77]

Over time, yes. It will over time gain more momentum

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3 years ago

What process is occurring in the picture?

Alex777 [14]

Two fat black arrows are swimming along together, when they see a single skinny black arrow coming toward them. They are afraid of strangers, and they know that the skinny one must be mean and tough if it's not afraid to travel alone. So they turn to the side and get out of the skinny arrow's way.

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3 years ago

A 4.0 m length of gold wire is connected to a 1.5 V battery, and a current of 4.0 mA flows through it. What is the diameter of t

sladkih [1.3K]

Explanation:

Given that,

Length of gold wire, l = 4 m

Voltage of battery, V = 1.5 V

Current, I = 4 mA

The resistivity of gold, $\rho=2.44\times 10^{-8}\ \Omega-m$

Resistance in terms of resistivity is given by :

$R=\dfrac{\rho l}{A}$

Also, V = IR

So,

$\dfrac{V}{I}=\dfrac{\rho l}{A}$

A is area of wire,

$\dfrac{V}{I}=\dfrac{\rho l}{\pi r^2}$ , r is radius, r = d/2 (diameter=d)

$\dfrac{V}{I}=\dfrac{\rho l}{\pi (d/2)^2}\\\\\dfrac{V}{I}=\dfrac{4\rho l}{\pi d^2}\\\\d=\sqrt{\dfrac{4\rho l I}{V\pi}} \\\\d=\sqrt{\dfrac{4\times 2.44\times 10^{-8}\times 4\times 4\times 10^{-3}}{1.5\times \pi}} \\\\d=18.2\ \mu m$

Out of four option, near option is (C) 17 μm.

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3 years ago